[PHP] Passing a class through an array
Hey all,
I'm very new to programming and PHP.
I want to pass instances of a class through an array, and then use a foreach
later to grab details of each class at once... but it returns a fatal error
Code:
$me = new Toon('Toon1','1')
$him = new Toon('Toon2','0')
$characterListing = array($me, $him);
foreach ($characterListing as $name1)
{
if ($name1->GetIsPlayer())
{
echo "Name: ".$name1->$name;// etc etc etc
}
}
the error I get is: Fatal error: Cannot access empty property in
c:\Inetpub\wwwroot\MyProjects\SecondOffering\htmlFns.php on line 140
Can anyone help?
Thanks, Jeff
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[PHP] Re: Troubles from the newb again
Is it possible to just add a value to the existing? here is my current
script:
foreach ($newarray as $name)
{
$newarray[$name] = $name->currentInitiative =
rand(1,$name->GetInitiative()));
}
// sort array by ranking (initiative)
sort($newarray,SORT_NUMERIC);
can I change the $newarray[$name] to something to represent the current
element and just add the value to it?
I might be able to work around it then
""Jeff Taylor"" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hey everyone,
> Newb back again - Im trying to populate my arrays, but getting this error
> again:
> Warning: Illegal offset type in
> c:\Inetpub\wwwroot\MyProjects\SecondOffering\myFuncs.php on line 242
>
> Code:
>$newarray = array();
>foreach ($array as $name)
>{
> if ($name->currentHP >0)
> {
> $newarray[$name];
> }
>}
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Re: [PHP] Troubles from the newb again
Yeah I have, but what I dont understand is that the value of $name is an
object, and was accepted in the original array as the index:
the original array was:
$me = new Toon(,xxx,xxx,,xxx,etc,etc,etc)
$him = new Toon(xxx,xx,x,etc,etc,etc,etc)
$array=array($me,$him)
So this new array, I want to isolate those toons still alive:
if alive then
add toon to new array
Is this possible in anyway?
The reason why I dont want it to put it in a value:
foreach ($newarray as $name)
{
if (in_array($name,$characters))
{
$newarray[$name] = 1;
}
else
{
$newarray[$name] = 2;
}
}
Sorry for the spam everyone
"Robert Cummings" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> On Sat, 2007-03-10 at 15:31 +1030, Jeff Taylor wrote:
> > Hey everyone,
> > Newb back again - Im trying to populate my arrays, but getting this
error
> > again:
> > Warning: Illegal offset type in
>
> This usually means that you are using a non-scalar value as an index.
> Use var_dump( $array ) to see what's in there. You will probably find
> one of the following: an array, and object, or the null value.
>
> Cheers,
> Rob.
> --
> ..
> | InterJinn Application Framework - http://www.interjinn.com |
> ::
> | An application and templating framework for PHP. Boasting |
> | a powerful, scalable system for accessing system services |
> | such as forms, properties, sessions, and caches. InterJinn |
> | also provides an extremely flexible architecture for |
> | creating re-usable components quickly and easily. |
> `'
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Re: [PHP] Passing a class through an array
Ahh the problem was that I was using $name1->$name instead of $name1->name
to call the variable.
Thanks though :)
> If line 140 is the $name1->name part, then you probably haven't
> written your constructor correctly to cram 'Toon1' into the name
> field...
>
>
> On Thu, March 8, 2007 11:51 pm, Jeff Taylor wrote:
> > Hey all,
> > I'm very new to programming and PHP.
> > I want to pass instances of a class through an array, and then use a
> > foreach
> > later to grab details of each class at once... but it returns a fatal
> > error
> >
> > Code:
> >
> > $me = new Toon('Toon1','1')
> > $him = new Toon('Toon2','0')
> >
> >$characterListing = array($me, $him);
> >
> >foreach ($characterListing as $name1)
> >{
> > if ($name1->GetIsPlayer())
> > {
> > echo "Name: ".$name1->$name;// etc etc etc
> > }
> >}
> >
> >
> >
> > the error I get is: Fatal error: Cannot access empty property in
> > c:\Inetpub\wwwroot\MyProjects\SecondOffering\htmlFns.php on line 140
> >
> > Can anyone help?
> >
> > Thanks, Jeff
> >
> >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >
> >
>
>
> --
> Some people have a "gift" link here.
> Know what I want?
> I want you to buy a CD from some starving artist.
> http://cdbaby.com/browse/from/lynch
> Yeah, I get a buck. So?
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[PHP] working with class inheritance
Hey all, got a slight problem, where for some reasons my variables dont seem
to be getting stored in the child class:
e.g
class Parent
{
$private type;
public function __construct()
{
}
public function GetType()
{
return $this->type;
}
}
class Child implements Parent
{
$public function __construct()
$this->type= 'Child';
}
}
$Child= new Child();
echo $Child->getType;
Can u see any reason why the type would return null?
Thanks,
Jeff
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[PHP] Re: working with class inheritance
OOPS!... typo
Please replace implements with extends:
class Child extends Parent
Sorry about that
""Jeff Taylor"" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hey all, got a slight problem, where for some reasons my variables dont
seem
> to be getting stored in the child class:
>
> e.g
>
> class Parent
> {
> $private type;
>
> public function __construct()
> {
> }
>
>public function GetType()
>{
> return $this->type;
> }
> }
>
> class Child implements Parent
> {
> $public function __construct()
>
>
> $this->type= 'Child';
> }
> }
>
> $Child= new Child();
> echo $Child->getType;
>
> Can u see any reason why the type would return null?
>
> Thanks,
>
> Jeff
>
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[PHP] Re: working with class inheritance
I forgot to mention that I have some __construct operations in the parent
class, and I want to add to those (and overwrite sometimes) in the child
class __construct
i.e Parent class __construct
$this->foo = 'Bar';
$this->foo2 = '10';
Child class __construct
$this->foo.='Bar';
$this->foo2 .= rand(1,6);
$this->type = 'Child';
Outputs of variables foo == Bar Bar
foo2 == 11-16
type == Child
Thanks :)
""Jeff Taylor"" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> OOPS!... typo
>
> Please replace implements with extends:
>
> class Child extends Parent
>
> Sorry about that
> ""Jeff Taylor"" <[EMAIL PROTECTED]> wrote in message
> news:[EMAIL PROTECTED]
> > Hey all, got a slight problem, where for some reasons my variables dont
> seem
> > to be getting stored in the child class:
> >
> > e.g
> >
> > class Parent
> > {
> > $private type;
> >
> > public function __construct()
> > {
> > }
> >
> >public function GetType()
> >{
> > return $this->type;
> > }
> > }
> >
> > class Child implements Parent
> > {
> > $public function __construct()
> >
> >
> > $this->type= 'Child';
> > }
> > }
> >
> > $Child= new Child();
> > echo $Child->getType;
> >
> > Can u see any reason why the type would return null?
> >
> > Thanks,
> >
> > Jeff
> >
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Re: [PHP] working with class inheritance
Thanks everyone,
Gave me a much better understanding of it
"Jim Lucas" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Jim Lucas wrote:
> > Jeff Taylor wrote:
> >> Hey all, got a slight problem, where for some reasons my variables
> >> dont seem
> >> to be getting stored in the child class:
> >>
> >> e.g
> >>
> >> class Parent
> > At least in PHP 5.2.1 on windows xp (for testing only), the class name
> > Parent is a reserved class name, you cannot define a class by that name.
> >
> >> {
> >> $private type;
> >>
> >> public function __construct()
> >> {
> >> }
> >>
> >>public function GetType()
> >>{
> >> return $this->type;
> >> }
> >> }
> >>
> >> class Child implements Parent
> >> {
> >> $public function __construct()
> > public should not be prefixed with '$'
> > you are missing your open '{' for this method
> >>
> >
> > You need to call
> > parent::__construct();
> >
> >>
> >> $this->type= 'Child';
> >> }
> >> }
> >>
> >> $Child= new Child();
> >> echo $Child->getType;
> > also, you are calling a method, not accessing a property.
> >
> > it should be
> > echo $Child->getType();
> >
> >>
> >> Can u see any reason why the type would return null?
> >>
> >> Thanks,
> >>
> >> Jeff
> >>
> >>
> > well, for starters, I think it is incorrect to have public and private
> > prefixed with a '$'. But then you have it on some, but not all of
> > them.
> >
> > Besides that, does it give you an error? What does it return if it
> > doesn't return 'Child'??
> >
> > What version of PHP are you running on. there is a differnet way the
> > constuct() method gets called.
> >
> > public and private are not available in versions older than php 5
> >
> > in PHP version < 5 you have to have a method named the same as the class
> > that you are creating.
> >
> > Try this:
> > >
> > class myParent {
> > #private $type;#<--- With this, I cannot echo $type
> >
> > var $type;#<--- With this, I CAN echo $type
> >
> > public function __construct() {
> > }
> >
> > public function myParent() {
> > $this->__construct();
> > }
> > public function getType() {
> > echo $this->type;
> > }
> > }
> >
> > class myChild extends myParent {
> > public function __construct() {
> > parent::__construct();
> > $this->type = 'Child';
> > }
> > public function myChild() {
> > $this->__construct();
> > }
> > }
> >
> > $Child = new myChild();
> > echo $Child->getType();
> >
> > ?>
> >
>
> ok, responded too quickly. Roman has it right with the settype method
>
> This now works.
>
>
> class myParent {
> private $type;
> public function __construct() {
> return $this;
> }
> public function myParent() {
> return $this->__construct();
> }
> public function setType($value='') {
> $this->type = $value;
> }
> public function getType() {
> return $this->type;
> }
> }
>
> class myChild extends myParent {
> public function __construct() {
> parent::__construct();
> $this->setType('Child');
> return $this;
> }
> public function myChild() {
> return $this->__construct();
> }
> }
>
> $Child = new myChild();
> echo $Child->getType();
>
> ?>
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