[PHP] FastCGI
Hi, obviously, I don't if this is the right newsgroup to ask such questions, but here it goes... what has happened with FastCGI support on the 4.3 version of PHP? On changelog I saw that SAPI/FastCGI was discontinued. But when I do phpinfo() it reports "Server API : CGI/FastCGI" and when I go with "php -v" the answer is: PHP 4.3.0 (cgi-fcgi), Copyright (c) 1997-2002 The PHP Group Zend Engine v1.3.0, Copyright (c) 1998-2002 Zend Technologies and when I go with "php -h" there's an option : -b | Bind Path for external FASTCGI Server mode But when I do "php -b localhost:5000" it says there's no "b" command. What's up with FastCGI? Was it really discontinued? If so, where can I find good alternatives to FastCGI for my home made webserver running on WinXP and where can I find the reasons that lead to this? thankz Fernando -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: PHP memory usage
I don't know if I'm talking bullshit, but don't forget that each parameter
or return valeu in php, if not explicited as a pointer, it's a copy of the
full parameter.
This way, any
function a(myclass c)
{
return c;
}
would create another copy of "c" in memory. Things get a bit larger when you
go with linked-list like structures in classes, where you have to take
really good care to don't duplicate data. If you're not taking care, then
maybe 5MB is normal.
IMHO, I agree with splitting the class into smaller functions. 370KB is a
big thing, that maybe useless. PHP isn't Java so you're not suposed to do a
"class mysite"
[]s
Fernando
"James H. Thompson" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> We have a good size PHP libary -- about 370KB of source code.
> Its one class with a multitude of small functions in it.
> just doing a require_once() on this library appears to use about 5MB of
> memory.(the change in VmSize in /proc/self/status)
>
> Is this a normal ratio of PHP source code size to executable size?
>
>
> --
> Jim
>
> James H. Thompson
> [EMAIL PROTECTED]
>
>
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[PHP] Re: DUMB QUESTION I'M SURE
on the line that starts with $query = there's an extra ."
the line should be:
$query = "SELECT shops.name FROM shops WHERE name = ".$name;
[]s
Fernando
"Adam French" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> I'm just starting out, this is my script...
>
> $name = $_POST['username'];
> $name = $name;
> $db = mysql_connect("localhost");
> mysql_select_db("vinyldealers",$db);
> $query = "SELECT shops.name FROM shops WHERE name = ".$name.";
> $result = mysql_query($query);
> while ($record = mysql_fetch_assoc($result)) {
> while (list($feildname, $feildvalue) = each ($record)) {
> echo $feildname. ": " .$feildvalue. "";
> }
> echo"";
> }
> ?>
>
> This is the error I get...
>
> Parse error: parse error, unexpected ':' in
> C:\Xitami\webpages\php\result1.php on line 12
>
> I dunno what I'm doing wrong. Help please???
>
>
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