[PHP] nested statement problem

[Eric Boerner]

I am having a problem with a nested if statement in php. Everything
works fine, but it doesn't display the information that I am trying to
retrieve using a second if statement.

CODE:

if (($fr == 'FR') && ($xe == 'XE') && ($co == 'CO')) { print
"Statement";
} elseif (($ag == 'AG') && ($rz == 'RZ') && ($sa == 'SA')) {
print "Additional Statement"; 
if ($sr == 'SR') { print "More Info"; }
 print "Line continuation";
if (($rx == 'RX') && ($rj == 'RJ') && ($rr == 'RR') &&
($rd == 'RD') && ($ra == 'RA')) { print "additional information"; }

// Everything works except this nested if statement - No php error, it
just doesn't display the information

 print "";
} else { print "other information if false"; }


ENDCODE:


Thanks in advance

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[PHP] Trouble with arrays from within MySQL results where clause

[Eric Boerner]

Hello all,

I am having trouble setting array data from within a MySQL results
query. I have modified data from the result and wish to enter it into
it's own array ($data). That then is used to generate a graph. The
following code basically gives me an empty array...

I am pulling out a timestamp and signal strength from a live data stream
to chart how strong a tower's signal is during the day. The data streams
once a minute from several sources. I compare each incoming signal with
the if statement and keep the highest signal strength. Each row is then
put into the new array.

CODE:

$data = array();
while ($row1 = mysql_fetch_row ($queryexe1)){

$datetime = $row1[2];
$sig1 = $row1[3]; 
$sig2 = $row1[6]; 
$sig3 = $row1[9]; 
list($date,$time) = explode(" ",$datetime);
if ($sig1 > "-150") { $aval = "$sig1"; }
if ($sig2 > "-150") { $bval = "$sig2"; } if ($bval > $aval)
{$aval = bval;}
if ($sig3 > "-150") { $bval = "$sig3"; } if ($bval > $aval)
{$aval = $bval;}

$data[] = array('$time' => '$time','$aval' => 'aval');

$aval = "-999";

}
$graph->SetDataValues($data);

END CODE:

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RE: [PHP] Trouble with arrays from within MySQL results where clause

[Eric Boerner]

Nevermind, I figured it out. Simple case of duh...

$data[] = array('$time' => '$time','$aval' => 'aval');

Should have been:

$data[] = array('$time' => "$time" ,'$aval' => "aval");

Thanks. :)

-Original Message-
From: Eric Boerner [mailto:[EMAIL PROTECTED] 
Sent: Monday, July 12, 2004 9:06 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Trouble with arrays from within MySQL results where
clause

Hello all,

I am having trouble setting array data from within a MySQL results
query. I have modified data from the result and wish to enter it into
it's own array ($data). That then is used to generate a graph. The
following code basically gives me an empty array...

I am pulling out a timestamp and signal strength from a live data stream
to chart how strong a tower's signal is during the day. The data streams
once a minute from several sources. I compare each incoming signal with
the if statement and keep the highest signal strength. Each row is then
put into the new array.

CODE:

$data = array();
while ($row1 = mysql_fetch_row ($queryexe1)){

$datetime = $row1[2];
$sig1 = $row1[3]; 
$sig2 = $row1[6]; 
$sig3 = $row1[9]; 
list($date,$time) = explode(" ",$datetime);
if ($sig1 > "-150") { $aval = "$sig1"; }
if ($sig2 > "-150") { $bval = "$sig2"; } if ($bval > $aval)
{$aval = bval;}
if ($sig3 > "-150") { $bval = "$sig3"; } if ($bval > $aval)
{$aval = $bval;}

$data[] = array('$time' => '$time','$aval' => 'aval');

$aval = "-999";

}
$graph->SetDataValues($data);

END CODE:

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