[PHP] Form Problem

[Chris Kwasneski]

I'm having a problem with a HTML form.  When it gets submitted, I keep 
getting an undefined variable error message.  And a blank page (aside from 
a 'Hi' written on it...).  I don't think its a problem with my install of 
PHP as other PHP code is running fine, but can't get it to print out this 
name.  I'm probably missing something simple, but I just can't figure it out.

Any help would be appreciated.

the form:


  
  My Form
  
  
  

  My name is:
   

  
  
  
  


Test2.php file:


Form test...


Hi 



The url that is getting passed to the file:

http://localhost/test2.php?YourName=Chris&submit=Submit

The error message I'm getting:


[Wed Jan 09 14:24:47 2002] [error] [client 127.0.0.1] PHP 
Warning:  Undefined variable:  YourName in c:\program files\apache 
group\apache\htdocs\test2.php on line 10





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Re: [PHP] MySql query

[Chris Kwasneski]

Try:

SELECT gallery_name,  image_id, image_name FROM galleries, Images WHERE 
galleries.gallery_id = images.gallery_id

At 07:57 AM 4/19/2002 -0700, you wrote:
>Ok this could be the wrong place to ask this but there seems to be some
>people in here that know mysql quite well.
>My question is this; I have a database that looks like this.
>galleries
>
>gallery_id
>gallery_name
>
>
>
>Images
>
>image_id
>gallery_id
>image_name
>etc
>
>
>
>I am trying to run a SQL query that will return an array of rows from the
>images table. But I want the gallery_id "number" to be replaced with the
>actual "gallery name" from the galleries table.


-Chris


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RE: [PHP] Parsing error

[Chris Kwasneski]

Is it just me or is the for statement missing a begining curly bracket?

-Chris



At 11:29 AM 4/1/2002 -0600, you wrote:
>which line is 45
>
>-Original Message-
>From: news.php.net [mailto:[EMAIL PROTECTED]]
>Sent: Monday, April 01, 2002 10:45 AM
>To: [EMAIL PROTECTED]
>Subject: [PHP] Parsing error
>
>
>Hi,
>
>I'm real new in php and trying to read a txt file
>
>this is my code :
>
>  $row = 1;
>  $fp = fopen ("lecteurs.txt","r");
>   while ($data = fgetcsv ($fp, 1000, ";"))
>   {
> $num = count ($data);
> $row++;
> for ($c=0; $c<$num; $c++)
> switch ($row)
>  {
>  case 1 :
>   {
>   $vignette = $data[$c];
>   }
>  case 2 :
>{
>$photo= $data[$c];
>}
>case 3 :
>{
>$marque= $data[$c];
>}
>   case 4 :
>{
>$nom = $data[$c];
>}
>   case 5 :
>{
>$pdfproduit= $data[$c];
>}
>   case 6 :
>{
>$commprod = $data[$c];
>}
> }
>   fclose ($fp);
>   echo $vignette;
>   echo $photo;
>   echo $marque;
>   echo $nom;
>   echo $pdfproduit;
>   echo $commprod;
>?>
>
>and when i run it i get : Parse error: parse error in essai.php on line 45
>
>here' my txt file (just 1 line for probe)
>
>petitimage;photo;marque;Nom;lepdf;commproduit
>
>Can someone help me to go thru
>
>TIA
>
>Hubert
>
>
>
>
>
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Re: [PHP] SELECT + PARSE ERROR

[Chris Kwasneski]

At 02:23 PM 4/8/2002 +0200, you wrote:
>Hy,
>
>I try to do a SELECT but when I test my code I Have a parse error.
>If someone can explain to me why.
>
>Code:
>
>$db = mysql_connect(newsmanga_db);
>$req = "SELECT * FROM dvds WHERE nomdvd='".$nom."".$i"' ";  /// PARSE 
>ERROR IN THIS LINE

Your missing a '.' after the $i .

-Chris


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