// here is the date. We wont worry about the time.
$processdate = "07/04/2004 14:45";
What about different formats like 07-04-2004 14:45:00
...You have a good point, Curt. We could modify the code just a little
bit for the same then. Instead of exploding with "/", we may opt for "-"
explosion. Typically, I have observed users using one specific format
for their entire application. A simple change in the function can make
the function suit their requirements.
// calling the function.
// 1 means the date is in a daylight savings time
// 0 means the date is not in a daylight savings time
one thing to note, not all zones, even in the US honor the
DST. this is a rather sepecific function.
...I believe Indiana and Arizona do not honor daylight savings time.
They switch back and forth from EST to CST (Indiana) and MST to PST
(Arizona) if I am not mistaken. If it is not applicable to a particular
user(s), they should not use this function. This function could be
useful for only those who intend to use it.
echo daylight($processdate);
// now the function
function daylight($mydate)
{
// separating the date and time
$datetime = explode(" ",$mydate);
// exploding the components of date
$dateexplode = explode("/",$datetime[0]);
Instead of exploding stuff around, make your date argument compatible
with the strtotime() function, it will return a unix timestamp or
-1 if it fails to parse the date.
...Good point. I should write something with strtotime(). Thank you.
// if the date is between Jan-Mar, NO DAYLIGHT
// if the date is between Nov-Dec, NO DAYLIGHT
if ($dateexplode[0]<4 or $dateexplode[0]>10)
{
return 0;
}
// if the date is not in the above zone, lets see
// if the date is between May-Sep, DAYLIGHT
elseif ($dateexplode[0]>4 and $dateexplode[0]<10)
{
return 1;
}
Since you have a timestamp as I suggested above, you simply need
to pull the month out, and then check the month value:
...I used the above method to indicate to users what is going on. I did
not use switch :: case because I did not want a month-to-month checking.
I wanted to check and process for only months 4 through 10 and for only
those dates in month 4 & 10 that made a difference between CST and CDT
(or any time zone change, in that case).
$month = strftime('%m', $utimestamp);
swtich ($month) {
case '01': case '02': ...
return 0;
case '05': case '06': ...
return 1;
}
else
{
// we are going to pull out what date is a sunday
// then we compare our date's day-of-month with the
day-that-is-sunday
$interestday = 0;
// lets see what happens in april - first sunday of the month
if ($dateexplode[0]==4)
{
// looping the first seven days to see what day is a
sunday
for ($i=1; $i<=7; $i++)
{
$myday =
date("w",mktime(0,0,0,$dateexplode[0],$i,$dateexplode[2]));
if ($myday==0)
$interestday = $i;
}
// now that we got what day is a sunday, lets see
// if our date's day-of-month is greater than this
or not
// if it is greater, then DAYLIGHT
if ($dateexplode[1]>=$interestday)
return 1;
else
return 0;
}
// lets see what happens in october - last sunday of the
month
elseif ($dateexplode[0]==10)
{
// looping the first seven days to see what day is a
sunday
for ($i=25; $i<=31; $i++)
{
$myday =
date("w",mktime(0,0,0,$dateexplode[0],$i,$dateexplode[2]));
if ($myday==0)
$interestday = $i;
}
// now that we got what day is a sunday, lets see
// if our date's day-of-month is greater than this
or not
// if it is less, then DAYLIGHT
if ($dateexplode[1]<=$interestday)
return 1;
else
return 0;
}
}
now instead of doing all that mundane work, we simply have to
find out if the days are outabounds for the paticular months.
...Your code looks neater. Thank you.
// obtain the day of month
$dayofmonth = (int)strftime('%d', $utimestamp);
// and the day of week
$dayofweek = strftime('%u', $utimestamp);
if ($month == '04') {
// If its the first week of 04
if ($dayofmonth <= 7) {
// and we havn't reached sunday, return 0
return ($dayofweek < 7) ? 0: 1;
}
return 1; // otherwise we're passed it.
} elseif ($month == '10') {
// look at the last week october
if ($dayofmonth >= 24) {
// see if we're still in the zone.
return ($dayofweek < 7) ? 1: 0;
}
return 1;
}
// something went wrong.
return -2;
}
Curt
...Thanks for your comments, Curt. Whenever I write a better code, I
will post it here.
Chirag Shukla.
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