Nested-Internal Functions
Hello , I have a query about creating nested functions in PostgreSQL. I am currently using PostgreSQL 15 and I am trying to create a nested function with the following structure: CREATE OR REPLACE FUNCTION external_function () RETURNS void AS $$ DECLARE external_variable; -- Define the internal function FUNCTION internal_function () RETURNS void AS $$ DECLARE internal_variable INT; BEGIN -- Internal function code internal_variable:= 10; RAISE NOTICE 'Internal Variable: %', internal_variable; END; $$ LANGUAGE plpgsql; BEGIN -- External function code external_variable:= 5; RAISE NOTICE 'External variable: %', external_variable; -- Call internal function PERFORM internal_function (); END; $$ LANGUAGE plpgsql; However, I get an error, and I can't compile the function. Thank you very much for your help Rossana Ocampos
AW: Nested-Internal Functions
Effectively I had to create the function externally, I am in the process of migrating from Oracle to Postgresql and I have many cases of encapsulated functions and transactions. Thank you very much for the return. Rossana Ocampos -Ursprüngliche Nachricht- Von: Laurenz Albe [mailto:laurenz.a...@cybertec.at] Gesendet: Dienstag, 16. Januar 2024 15:42 An: Rossana Ocampos; pgsql-general@lists.postgresql.org Betreff: Re: Nested-Internal Functions On Tue, 2024-01-16 at 13:15 +0100, Rossana Ocampos wrote: > I have a query about creating nested functions in PostgreSQL. There are no "nested functions" in PostgreSQL. You'd need to rewrite that to use a proper stand-alone function. Yours, Laurenz Albe
CURRENTE_DATE
Hello , I am new with PostgreSQL and I have a bug. I have created a function that has an input variable of type date , in case it does not receive value , it has to assume by default the current date. I have defined it as follows variable DATE DEFAULT CURRENT_DATE, but I get the following error. El error ERROR: invalid input syntax for type date: "CURRENT_DATE" LINE 1: ...extsupplydate ('1085018'::bigint, '5278'::bigint, 'CURRENT_D... ^ ERROR: invalid input syntax for type date: "CURRENT_DATE" SQL status: 22007 Characters: 78 Please could you help me, thank you very much. Rossana