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PIPESTATUS within assignment statements.
a=$(COMMAND1 | COMMAND2 | COMMAND3)
How can I get return status from COMMAND2?
Configuration Information [Automatically generated, do not change]:
Machine: i486
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i486'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i486-pc-linux-gnu'
-DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL
-DHAVE_CONFIG_H -I. -I../bash -I../bash/include -I../bash/lib -g -O2
uname output: Linux pepinux 2.6.18-1-686 #1 SMP Mon Sep 25 00:42:11 UTC 2006
i686 GNU/Linux
Machine Type: i486-pc-linux-gnu
Bash Version: 3.1
Patch Level: 17
Release Status: release
Description:
host$ a=$(COMMAND1 | COMMAND2 | COMMAND3)
host$ echo ${PIPESTATUS[1]}
returnstatus_command2
host$
Repeat-By:
host$ a=$(COMMAND1 | COMMAND2 | COMMAND3)
host$ echo ${PIPESTATUS[1]}
Fix:
host$ set -o pipefail or anything similar
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Processing a file into smaller chunks
Dear all,
I'm a newbie with bash programming and I'm trying to process a file
into smaller
chunks. Let's say I've to process the file below ('X' and 'Y' are any
possible float number):
0 0 0 0 0 0
0 0 0 0 0 0
X X X X X 1.70
0 0 0 0 0 0
X X X X X 1.60
0 0 0 0 0 0
X X X X X 1.30
Y Y Y Y Y 1.90
0 0 0 0 0 0
0 0 0 0 0 0
X X X X X 2.10
The lines containing 0’s can be thought as being delimiters. I need to
find between the delimiters, which line has the highest value in the
last column (column#6), and, just output the corresponding line. Does
anybody could shed some light on it? An example of the desired output
would be:
X X X X X 1.70
X X X X X 1.60
Y Y Y Y Y 1.90
X X X X X 2.10
Is it possible to obtain such a result using bash scripting?
Best regards
string to integer
Dear all,
I have a several directories with *.jpg images. The image files are
named as ascending numbers and I would like to retrieve the lowest and
largest image number in each directory. An example of the content of a
directory is given below:
/bla/bla/bla/dir1
-> 0.jpg
-> 1.jpg
->
-> 09001.jpg
The desired output would be the integer numbers: 0 and 9001
With the code below, I'm able to retrieve in "seqInterval" array,
which is the lowest and largest image number as strings.
seqDir="/bla/bla/bla/dir1"
seqInterval=($(find $seqDir -name "*.jpg" | sort | sed -n -e '1p;$p' |
sed -e 's|^.*/||' -e 's/\.[^.]*$//'))
in our example, I obtain sth. like:
seqInterval[0] is equal to "0" and seqInterval[1] is equal to
"09001"
Since those are string numbers, I was wondering which is the best way
to convert those strings into integer numbers (seqInterval[0]=0 and
seqInterval[1]=9001)?
I tried the code below, but it doesn't work properly, any suggestions?
startImg=$(printf '%d' ${seqInterval[0]})
endImg=$((printf '%d' ${seqInterval[1]}))
Best whishes
Re: string to integer
On Mar 19, 12:39 pm, Javier Montoya wrote:
> Dear all,
>
> I have a several directories with *.jpg images. The image files are
> named as ascending numbers and I would like to retrieve the lowest and
> largest image number in each directory. An example of the content of a
> directory is given below:
> /bla/bla/bla/dir1
> -> 0.jpg
> -> 1.jpg
> ->
> -> 09001.jpg
>
> The desired output would be the integer numbers: 0 and 9001
> With the code below, I'm able to retrieve in "seqInterval" array,
> which is the lowest and largest image number as strings.
> seqDir="/bla/bla/bla/dir1"
> seqInterval=($(find $seqDir -name "*.jpg" | sort | sed -n -e '1p;$p' |
> sed -e 's|^.*/||' -e 's/\.[^.]*$//'))
> in our example, I obtain sth. like:
> seqInterval[0] is equal to "0" and seqInterval[1] is equal to
> "09001"
> Since those are string numbers, I was wondering which is the best way
> to convert those strings into integer numbers (seqInterval[0]=0 and
> seqInterval[1]=9001)?
>
> I tried the code below, but it doesn't work properly, any suggestions?
> startImg=$(printf '%d' ${seqInterval[0]})
> endImg=$((printf '%d' ${seqInterval[1]}))
>
> Best whishes
Dear all,
I found a solution:
startImg=$(printf '%d' ${seqInterval[0]//0/})
endImg=$(printf '%d' ${seqInterval[1]//0/})
Is there's a better way, pls let me know!
Re: string to integer
On Mar 19, 6:04 pm, DennisW wrote:
> On Mar 19, 6:50 am, Javier Montoya wrote:
>
>
>
> > On Mar 19, 12:39 pm, Javier Montoya wrote:
>
> > > Dear all,
>
> > > I have a several directories with *.jpg images. The image files are
> > > named as ascending numbers and I would like to retrieve the lowest and
> > > largest image number in each directory. An example of the content of a
> > > directory is given below:
> > > /bla/bla/bla/dir1
> > > -> 0.jpg
> > > -> 1.jpg
> > > ->
> > > -> 09001.jpg
>
> > > The desired output would be the integer numbers: 0 and 9001
> > > With the code below, I'm able to retrieve in "seqInterval" array,
> > > which is the lowest and largest image number as strings.
> > > seqDir="/bla/bla/bla/dir1"
> > > seqInterval=($(find $seqDir -name "*.jpg" | sort | sed -n -e '1p;$p' |
> > > sed -e 's|^.*/||' -e 's/\.[^.]*$//'))
> > > in our example, I obtain sth. like:
> > > seqInterval[0] is equal to "0" and seqInterval[1] is equal to
> > > "09001"
> > > Since those are string numbers, I was wondering which is the best way
> > > to convert those strings into integer numbers (seqInterval[0]=0 and
> > > seqInterval[1]=9001)?
>
> > > I tried the code below, but it doesn't work properly, any suggestions?
> > > startImg=$(printf '%d' ${seqInterval[0]})
> > > endImg=$((printf '%d' ${seqInterval[1]}))
>
> > > Best whishes
>
> > Dear all,
>
> > I found a solution:
>
> > startImg=$(printf '%d' ${seqInterval[0]//0/})
> > endImg=$(printf '%d' ${seqInterval[1]//0/})
>
> > Is there's a better way, pls let me know!
>
> In the case of 09001 your command results in "91"
>
> Try:
>
> shopt -s extglob
> printf '%d' ${seqInterval[0]/#*(0)/}
> printf '%d' ${seqInterval[1]/#*(0)/}
>
> which says "delete a sequence of zero or more '*()' zeros anchored at
> the beginning '#' of the string"
Thanks Dennis! But in the case of 00, I obtain an empty value.
Ideally, I should keep just one zero.
Best wishes
