typeset does not make variable local in function
Problem:
typeset, when used in a function should always mark the variable as local.
When bash is in ksh mode, it fails to do this.
Previous versions did not have this problem, e.g.
GNU bash, version 3.00.15(1)-release (i386-redhat-linux-gnu)
Recent versions of ksh seem to be exhibiting the same bug.
System:
Linux XXX 2.6.20-1.2948.fc6 #1 SMP Fri Apr 27 19:48:40 EDT 2007 i686 i686 i386
GNU/Linux
GNU bash, version 3.1.17(1)-release-(i686-redhat-linux-gnu)
Login shell = /bin/bash
Reproduction:
x1:
#!/bin/bash
F1 () {
typeset T1
T1="Wrong!"
}
echo "Before=$T1"
F1
echo "After=$T1"
x2:
#!/bin/ksh
F1 () {
typeset T1
T1="Wrong!"
}
echo "Before=$T1"
F1
echo "After=$T1"
/bin/bash
./x1
Before=
After=
exit
/bin/bash
./x2
Before=
After=Wrong!
exit
/bin/bash -c ". ./x1"
Before=
After=
/bin/bash -c ". ./x2"
Before=
After=
/bin/ksh -c ". ./x1"
Before=
After=Wrong!
/bin/ksh -c ". ./x2"
Before=
After=Wrong!
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Re: typeset does not make variable local in function
I traced the problem down to the ksh that comes packaged with fedora core. bash is Fine. ksh is broken. On Wed, 6 Jun 2007 23:01 -0400, Chet Ramey quoth thus: > Clay Harris wrote: > > Problem: > > > > typeset, when used in a function should always mark the variable as local. > > When bash is in ksh mode, it fails to do this. > > I can't reproduce this with bash-3.0, bash-3.1, or bash-3.2 (all patched) > on MacOS X and FC6. Bash does not have a `ksh mode'. > > Chet ___ Bug-bash mailing list Bug-bash@gnu.org http://lists.gnu.org/mailman/listinfo/bug-bash
