Re: possible bash bug bringing job. to foreground
I was unaware of TMOUT. Now I have a backup as well. Thanks for tolerating my inexperience. On Sat, Feb 17, 2024 at 2:54 PM, Greg Wooledge wrote: On Sat, Feb 17, 2024 at 07:41:43PM +, John Larew wrote: > After further examination, the examples with "fg $$" and "fg $!" clearly do > not bring the subshell into the foreground, as they are evaluated prior to > the subshells background execution. > I'm trying to bring the subshell to the foreground to perform an exit, after > a delay. > Ultimately, it will be used as part of a terminal emulator inactivity timeout. Bash already has a TMOUT variable which will cause an interactive shell to exit after a specified length of inactivity. Is that sufficient? If not, how does your desired solution need to differ from TMOUT?
Inconsistent treatment of left-hand side of conditional expression where IFS is not its default value
Hi, This report stems from the discussion at https://lists.gnu.org/archive/html/help-bash/2024-02/msg00085.html. Consider the following two cases. $ ( set a -- b; f=+ IFS=$f; [[ $f$*$f == *"$f--$f"* ]]; echo $? ) 0 $ ( set a -- b; f=$'\1' IFS=$f; [[ $f$*$f == *"$f--$f"* ]]; echo $? ) 1 It does not make sense that that the exit status value differs between these cases, especially since SOH is not a whitespace character (in the sense of field splitting). I think that the second case should also yield 0. Regardless of what the intended behaviour is, I would also expect for the manual to describe it. Note that quoting the left-hand side fixes it for SOH. In the absence of quotes, xtrace output suggests that all of the SOH characters are stripped from the expansion of $f$*$f. $ ( set a -- b; f=$'\1' IFS=$f; [[ "$f$*$f" == *"$f--$f"* ]]; echo $? ) 0 -- Kerin Millar
Re: Inconsistent treatment of left-hand side of conditional expression where IFS is not its default value
On Sun, Feb 18, 2024, at 5:03 PM, Kerin Millar wrote: > Hi, > > This report stems from the discussion at > https://lists.gnu.org/archive/html/help-bash/2024-02/msg00085.html. > > Consider the following two cases. > > $ ( set a -- b; f=+ IFS=$f; [[ $f$*$f == *"$f--$f"* ]]; echo $? ) > 0 > > $ ( set a -- b; f=$'\1' IFS=$f; [[ $f$*$f == *"$f--$f"* ]]; echo $? ) > 1 > > It does not make sense that that the exit status value differs between > these cases, especially since SOH is not a whitespace character (in the > sense of field splitting). I think that the second case should also > yield 0. Regardless of what the intended behaviour is, I would also > expect for the manual to describe it. > > Note that quoting the left-hand side fixes it for SOH. In the absence > of quotes, xtrace output suggests that all of the SOH characters are > stripped from the expansion of $f$*$f. > > $ ( set a -- b; f=$'\1' IFS=$f; [[ "$f$*$f" == *"$f--$f"* ]]; echo $? ) > 0 Case commands exhibit similar behavior: $ set a -- b $ (f=+ IFS=$f; case $* in *"$f"*) echo 0;; *) echo 1;; esac) 0 $ (f=$'\1' IFS=$f; case $* in *"$f"*) echo 0;; *) echo 1;; esac) 1 $ (f=$'\1' IFS=$f; case "$*" in *"$f"*) echo 0;; *) echo 1;; esac) 0 -- vq
