Problem in var substitution with / and \
Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -march=x86-64 -mtune=generic -O2 -pipe
-fstack-protector-strong -fno-plt
-DDEFAULT_PATH_VALUE='/usr/local/sbin:/usr/local/bin:/usr/bin'
-DSTANDARD_UTILS_PATH='/usr/bin' -DSYS_BASHRC='/etc/ba>
uname output: Linux euler 4.20.0-arch1-1-ARCH #1 SMP PREEMPT Mon Dec 24
03:00:40 UTC 2018 x86_64 GNU/Linux
Machine Type: x86_64-pc-linux-gnu
Bash Version: 5.0
Patch Level: 0
Release Status: release
Description:
If a variable contains one '/' (or many)
and if this '/' is escaped with '\' by substitution mechanism
and if the escaped variable is concatenated with a string containing '/'
as prefix, and another string containing '/' as suffix
then all characters in prefix and suffix are escaped with '\'
The problem does not occurs in a "" context
Repeat-By:
URL=http://example.com
ESCAPED_URL=${URL//\//\\\/}
echo 'My URL: '$ESCAPED_URL' ... OK'
echo '/My URL: http:\/\/example.com ... OK/'
echo "/My URL: $ESCAPED_URL ... OK/"
echo '/My URL: '$ESCAPED_URL' ... KO/'
Re: Problem in var substitution with / and \
On Mon, Jan 14, 2019 at 12:51:37PM +0100, Jean-François Berroyer wrote:
> If a variable contains one '/' (or many)
> and if this '/' is escaped with '\' by substitution mechanism
> and if the escaped variable is concatenated with a string containing '/' as
> prefix, and another string containing '/' as suffix
> then all characters in prefix and suffix are escaped with '\'
> The problem does not occurs in a "" context
>
> Repeat-By:
> URL=http://example.com
> ESCAPED_URL=${URL//\//\\\/}
> echo 'My URL: '$ESCAPED_URL' ... OK'
> echo '/My URL: http:\/\/example.com ... OK/'
> echo "/My URL: $ESCAPED_URL ... OK/"
> echo '/My URL: '$ESCAPED_URL' ... KO/'
I cannot reproduce whatever problem you're seeing.
wooledg:~$ bash-5.0
wooledg:~$ URL=http://example.com
wooledg:~$ ESCAPED_URL=${URL//\//\\\/}
wooledg:~$ echo 'My URL: '$ESCAPED_URL' ... OK'
My URL: http:\/\/example.com ... OK
wooledg:~$ echo "/My URL: $ESCAPED_URL ... OK/"
/My URL: http:\/\/example.com ... OK/
Looks correct to me. What output are you getting?
Re: Problem in var substitution with / and \
On 1/14/19 6:51 AM, Jean-François Berroyer wrote:
> Bash Version: 5.0
> Patch Level: 0
> Release Status: release
>
> Description:
> If a variable contains one '/' (or many)
> and if this '/' is escaped with '\' by substitution mechanism
> and if the escaped variable is concatenated with a string containing '/' as
> prefix, and another string containing '/' as suffix
> then all characters in prefix and suffix are escaped with '\'
> The problem does not occurs in a "" context
>
> Repeat-By:
> URL=http://example.com
> ESCAPED_URL=${URL//\//\\\/}
> echo 'My URL: '$ESCAPED_URL' ... OK'
> echo '/My URL: http:\/\/example.com ... OK/'
> echo "/My URL: $ESCAPED_URL ... OK/"
> echo '/My URL: '$ESCAPED_URL' ... KO/'
See if this fixes it:
http://lists.gnu.org/archive/html/bug-bash/2019-01/msg00087.html
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRUc...@case.eduhttp://tiswww.cwru.edu/~chet/
