[[ -z ]] nullglob problem?
Configuration Information [Automatically generated, do not change]: Machine: i686 OS: linux-gnu Compiler: gcc Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i686' -DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i686-pc-linux-gnu' -DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL -DHAVE_CONFIG_H -I. -I. -I./include -I./lib -O2 -march=pentium-m -mmmx -msse -pipe uname output: Linux miranda 2.6.23 #3 PREEMPT Wed Oct 17 21:07:21 CEST 2007 i686 i686 i386 GNU/Linux Machine Type: i686-pc-linux-gnu Bash Version: 3.1 Patch Level: 0 Release Status: release Description: [[ -z seem to handle nullglob variables incorrect. See the Repeat-By below. Repeat-By: mkdir empty shopt -s nullglob if [[ -z empty/* ]] then echo empty fi Shouldn't this echo empty? echo empty/* echoes nothing, as it should since nullglob is set. However, the test if [[ -z empty/* ]] evaluates to false, not true as it should. Or shouldn't it? This works with [ anyway: if [ -z empty/* ] then echo empty fi echoes empty. Fix: Use [ instead of [[. -- Using Opera's revolutionary e-mail client: http://www.opera.com/mail/
Re: [[ -z ]] nullglob problem?
> Machine Type: i686-pc-linux-gnu > > Bash Version: 3.1 > Patch Level: 0 > Release Status: release > > Description: > [[ -z seem to handle nullglob variables incorrect. > See the Repeat-By below. > > Repeat-By: > > mkdir empty > shopt -s nullglob > if [[ -z empty/* ]] > then > echo empty > fi > > Shouldn't this echo empty? No, since, as documented, the conditional operator does not perform pathname expansion on its operands. Chet -- ``The lyf so short, the craft so long to lerne.'' - Chaucer Live Strong. Chet Ramey, ITS, CWRU[EMAIL PROTECTED]http://tiswww.tis.case.edu/~chet/
