On Fri, Jul 27, 2018 at 12:50 AM Steven D'Aprano wrote:
>
> On Thu, Jul 26, 2018 at 11:34:11PM -0500, boB Stepp wrote:
> > (1) The author claims that reStructuredText is the official Python
> > documentation standard. Is this true? If yes, is this something I
> > should be doing for my own proj
On 07/27/2018 11:23 AM, boB Stepp wrote:
> On Fri, Jul 27, 2018 at 12:50 AM Steven D'Aprano wrote:
>>
>> On Thu, Jul 26, 2018 at 11:34:11PM -0500, boB Stepp wrote:
>
>>> (1) The author claims that reStructuredText is the official Python
>>> documentation standard. Is this true? If yes, is this
On 01/07/2018 11:19, Steven D'Aprano wrote:
On Sun, Jul 01, 2018 at 03:32:59PM +1000, Chris Roy-Smith wrote:
"Save As..." before engaging in big changes is your friend :-)
Even better would be to learn a form of VCS (version control system)
such as Mercurial (hg) or git. Depending on the te
Hi all, I started studying python and I hope you may help me getting better.
Let's start with the first question.
Consider this example
---
#!/usr/bin/python3
l = ['unoX', 'dueX']
c = 0
for n in l:
l[c] = l[c].replace('X','')
c = c + 1
print (l)
---
it works but I wonder if ther
On 27/07/18 11:55, Shall, Sydney wrote:
> On 01/07/2018 11:19, Steven D'Aprano wrote:
>> Even better would be to learn a form of VCS (version control system)
>> such as Mercurial (hg) or git. Depending on the text editor you are
>> using, it may have VCS integration available.
>
> Does Spyder have
On 27/07/18 13:56, Valerio Pachera wrote:
> l = ['unoX', 'dueX']
> c = 0
> for n in l:
> l[c] = l[c].replace('X','')
> c = c + 1
> print (l)
> ---
>
> it works but I wonder if there's a better way to achieve the same.
Yes, a much better way.
for index, s in l:
l[index] = s.re
On 27Jul2018 23:06, Alan Gauld wrote:
On 27/07/18 13:56, Valerio Pachera wrote:
l = ['unoX', 'dueX']
c = 0
for n in l:
l[c] = l[c].replace('X','')
c = c + 1
print (l)
it works but I wonder if there's a better way to achieve the same.
Yes, a much better way.
for index, s in
On 27/07/18 23:32, Cameron Simpson wrote:
>> for index, s in l:
>> l[index] = s.replace('X','')
>> print(l)
>
> I think you meant:
>
> for index, s in enumerate(l):
Oops, yes. Sorry.
>> In Python you very rarely need to resort to using indexes
>> to process the members of a collection. And
On 07/27/2018 04:32 PM, Cameron Simpson wrote:
> On 27Jul2018 23:06, Alan Gauld wrote:
>> In Python you very rarely need to resort to using indexes
>> to process the members of a collection. And even more rarely
>> do you need to manually increment the index.
I think this was an important point:
