I have not checked the rest of your code, but:
> for line in seqalign:
> for i in len(finalmotif_seqs): # for item in finalmotif_seqs:
> for i in len(finalmotif_annot): # for item in finalmotif_annot:
I see two problems here:
1. You are using the same loop variable in both lo
Hi,
I am learning python and I am trying to write a simple "guess the number"
game. I wrote the program in the IDLE, and I set the variable tries=1 to keep
up
with the number of tries it takes to guess the number, but when I try to run
the
program it gives the error message "improper syntax"
On Thu, May 5, 2011 at 2:19 AM, Kyle Benak wrote:
> I am learning python and I am trying to write a simple "guess the number"
> game. I wrote the program in the IDLE, and I set the variable tries=1 to
> keep up with the number of tries it takes to guess the number, but when I
> try to run the pro
"Kyle Benak" wrote
I am learning python and I am trying to write a simple "guess the
number"
game. I wrote the program in the IDLE, and I set the variable
tries=1 to keep up
with the number of tries it takes to guess the number, but when I
try to run the
program it gives the error message "i
"louis leichtnam" wrote
I'm trying to write a program that looks in a webpage in find the
titles of
a subsection of the page:
Can you help me out? I tried using regular expression but I keep
hitting
walls and I don't know what to do...
Regular expressions are the wrong tool for parsing H
On 5/4/2011 10:30 AM, Patrick P. wrote:
Hello,
I hope this is the right way to ask my question, if not, sorry to bother
you. Maybe you can tell me who to ask.
Ok so here is my code
[snip]
A = np.array([[m111,m121], [m211,m221]])
B = np.array([[m112,m122], [m212,m222]])
print(np.dot(A,B))
Trac
On 5/4/2011 6:59 PM, Alan Gauld wrote:
The string methods are builtin and the string
module is really only needed for backwatds
compatibility these days.
Yes, except for:
8.1.5. String functions
The following functions are available to operate on string and Unicode
objects. They are not avai
> string.capwords(s[, sep])
So capwords is a little bit different but you can use a combination of split()
and title() to do some of it. Title() will work for the default case, but if
you split on non-whitespace then you will need to manually use split().
'test test test'.title()
'Test Test Test'
HEllo everyone,
I have a dictionnary, and I would like to print only the values that have
more/equal than 3 spaces in them for example: My name is Xavier.
Can you help me out,
Thanks
Louis
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Supposing your dictionary like this: dict={1:'My name is X',2:'My name is x
y z',3: 'i am X'}
You can use len(list) :
>>> dict={1:'My name is X',2:'My name is x y z',3: 'i am X'}
>>> for values in dict.values():
... if len(values.split(' '))>3:
...print values
My name is X
My name is x
louis leichtnam wrote:
HEllo everyone,
I have a dictionnary, and I would like to print only the values that have
more/equal than 3 spaces in them for example: My name is Xavier.
d = {1: "Hello world", 2: "My name is Xavier", 3: "ham and eggs",
4: "Eat more cheese please!", 5: "spam spam
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