> database and display customer information on web. ok, easy enough.
> heres the trick. the database is MS Access. - ick.
ick indeed, but maybe for different reasons...
There is an ODBC database driver that you can use to
access Access. But you will have to be careful about
locking if the
Hey there,
i have some log files that i want to be able to work with.
the lines of the log files are comma - delineated.
i want to put those into a database where each piece of info (comma
delineated)
would be the fields of the database.
ok, so the first obstacle is learning how to make a list or
nephish wrote:
> Hey there,
> i have some log files that i want to be able to work with.
> the lines of the log files are comma - delineated.
> i want to put those into a database where each piece of info (comma
> delineated)
> would be the fields of the database.
>
> ok, so the first obstacle is
Greetings again helpful friends,
I've written a series of Python/Tkinter programs, each of which will represent
a different menu/screen in a simple Tkinter game I'm making. Now, my trouble is
linking them together through layered menus with buttons.
So far, I've tried using a single Tk window, c
I have a dictionary called Menu_Main:
Menu_Main = { 1: ['People', Call_Fam],
2: ['Groups', Call_Group],
3: ['Events', nullfunc],
4: ['Attendance', nullfunc],
5: ['Visitation', nullfunc],
6: ['Finances', nullfunc],
Hello Tutors,
What would be the most Pythonic way of printing (or extracting) every
other element of a list? Thanks in advance.
-- Chuck Allison
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Quoting Phillip Hart <[EMAIL PROTECTED]>:
> So far, I've tried using a single Tk window, creating a series of canvas
> widgets, each containing a series of buttons. When pressed, each button
> calls a function which uses .grid_remove() on the current canvas and
> creates a new canvas with new butt
Quoting Chuck Allison <[EMAIL PROTECTED]>:
> Hello Tutors,
>
> What would be the most Pythonic way of printing (or extracting) every
> other element of a list? Thanks in advance.
This is probably it:
>>> arr = range(20)
>>> arr[::2]
[0, 2, 4, 6, 8, 10, 12, 14, 16, 18]
>>> arr[1::2]
[1, 3, 5, 7
DC Parris said unto the world upon 20/06/2005 01:13:
> I have a dictionary called Menu_Main:
>
> Menu_Main = { 1: ['People', Call_Fam],
> 2: ['Groups', Call_Group],
> 3: ['Events', nullfunc],
> 4: ['Attendance', nullfunc],
> 5: ['Vi