Hi,
I'm not exactly sure if the following is actually a bug or whether bash
is actually supposed to behave like this. However, I couldn't find any
documentation concerning it so I decided to ask.
The thing I noticed is that when setting a variable and then running the
command "time", bash reports
$ time;
real0m0.000s
user0m0.000s
sys 0m0.000s
$ time;ls
bash: syntax error near unexpected token `ls'
$ /usr/bin/time;/bin/ls
Usage: /usr/bin/time [-apvV] [-f format] [-o file] [--append] [--verbose]
[--portability] [--format=format] [--output=file] [--version]
[--qui
Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='x86_64'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='x86_64-pc-linux-gnu'
-DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKA
2009/10/16 Chet Ramey :
> You need to remember that readline understands the characters in
> rl_completer_quote_characters as those which, in pairs, delimit quoted
> substrings in the line. It performs completion (allowing the application
> to take first crack, of course) on the substring, using
Full Article:
http://service.spiegel.de/cache/international/0,1518,353274,00.html
___
Bug-bash mailing list
Bug-bash@gnu.org
http://lists.gnu.org/mailman/listinfo/bug-bash