Ok, I made a typo in the original post.  I actually divided by 6000, but
only typed 600 in my post.  Anyway:
137291046 bytes / 6000 sec = 22882 bytes/sec = 22 Kbytes/sec

which still seems pretty fast for my 33.6 modem...

-Mark-

On Wed, 5 Apr 2000, Chris Dowling wrote:

> perhaps divide by 6000 instead?
> 
> 100 minutes = 60 seconds * 100 = 6000 seconds
> 
> 137291046 / 6000 = 2.1k/s (approx)
> 
> On Tue, 4 Apr 2000, Mark Ivey wrote:
> 
> > Ok, today I check my log and I see this entry:
> > 
> > 
> > Apr  4 18:18:26 dimrill pppd[267]: Terminating connection due to lack of 
> > activity.
> > Apr  4 18:18:26 dimrill pppd[267]: Connection terminated.
> > Apr  4 18:18:26 dimrill pppd[267]: Connect time 100.6 minutes.
> > Apr  4 18:18:26 dimrill pppd[267]: Sent 17054927 bytes, received 137291046
> > bytes.
> > 
> > and I think "that is a lot of bytes recieved..." so I divide 137291046 by
> > 600 and come up with 21227.  Now, I'm pretty sure I don't have a modem
> > that can transfer at 21K/s so what is going on here?
> > 
> > -Mark-
> > 
> > 
> > -- 
> > To unsubscribe: mail [EMAIL PROTECTED] with "unsubscribe"
> > as the Subject.
> > 
> > 
> 
> 
> Chris Dowling.
> [EMAIL PROTECTED]
> 
> A bus station is where a bus stops.
> A train station is where a train stops.
> On my desk, I have a work station......
> 
> 
> -- 
> To unsubscribe: mail [EMAIL PROTECTED] with "unsubscribe"
> as the Subject.
> 


-- 
To unsubscribe: mail [EMAIL PROTECTED] with "unsubscribe"
as the Subject.

Reply via email to