* [EMAIL PROTECTED]
> #!/bin/bash
> 1st_arg=$1
number not allowed in front.
> prosesses=`lsof -i`
> prosessid=`echo $prosesses | gawk /1st_arg/'{print $2}'`
Cannot understand this to work in gawk. In any case, you might do
this a lot more effective:
> echo $prosessid
> if [ -z "$prosessid" ]
missing "then"
> echo "not running"
> fi
> exit 0
Not necessary
My suggestion:
#!/bin/bash
process=`lsof -i | grep $1 | gawk '{print $2 }'`
if [ "$process" = "" ]; then
echo "not running"
else
echo $process
fi
--
Jon Haugsand, [EMAIL PROTECTED]
http://www.norges-bank.no
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