Alan Manuel Gloria:
> Wouldn't this be better?  AFAIK list? implies pair?

Well yes, list? implies pair?, but I was thinking about performance.  After 
all, list? has to walk all the cons pairs' cdrs, while pair?() just has to look 
at one pair.  Typically lists aren't that long, but they could be, so I put the 
cheap operations first.  The memq does have to walk a list, but it's a 
relatively short invariant list, so it's a known-bounded-time operation.

> Yeah looks purty.

Cool!

--- David A. Wheeler

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