My understanding is that you can shadow `foo`, but you cannot use `foo` in any expression at the same scope where the struct's bindings appear. In this context, some of `foo`'s lexical information is reserved so that `struct-out` works correctly.
On 6/3/21 5:01 PM, flirora wrote: > Am I correct in assuming that given a definition like > > (struct foo (x) #:constructor-name bar) > > I then can't define something named foo in the same module, even though > there's no constructor called foo? > > -- > You received this message because you are subscribed to the Google Groups > "Racket Users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To view this discussion on the web visit > [https://groups.google.com/d/msgid/racket-users/02598ee4-4461-4815-bd4f-a8ac02c1118cn%40googlegroups.com](https://groups.google.com/d/msgid/racket-users/02598ee4-4461-4815-bd4f-a8ac02c1118cn%40googlegroups.com?utm_medium=email&utm_source=footer). -- ~slg -- You received this message because you are subscribed to the Google Groups "Racket Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/racket-users/76c51dda-b80d-d74a-c691-d92fe11008e8%40sagegerard.com.
