On Wed, 2010-06-02 at 08:07 -0400, Petr PIKAL wrote:
> Dear all
>
> I encountered strange problem with regexpr replacement
>
> I made this character object
>
> str <- "02.06.10 12:40 "
>
> > str(str)
> chr "02.06.10 12:40 "
>
> I read in an object which seems to be quite similar
>
> > str(as.character(becva$V1)[1])
> chr "02.06.10 12:40 "
>
> However I can not remove trailing spaces from it
>
> > sub(' +$', '', as.character(becva$V1[1]))
>
> [1] "02.06.10 12:40 "
> > sub(' +$', '', str)
> [1] "02.06.10 12:40"
> >
>
> Do somebody have an idea what to do?
Could the white space in the string be a tab? If so, the space character
will not match. Try something that matches multiple white space, like
sub('\\w+$', '', as.character(becva$V1[1]))
or
sub('[[:blank:]]+$', '', as.character(becva$V1[1]))
Matt Shotwell
Graduate Student
Division of Biostatistics and Epidemiology
Medical University of South Carolina
>
> $version.string
> [1] "R version 2.12.0 Under development (unstable) (2010-04-25 r51820)"
>
> on Windows
>
> Regards
> Petr
>
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