Hello Linda,
The "problem" is actually the median of your data. What the function
median.test() does first is combine both groups. Look at this:
median(c(group1, group2))
the median is 1, but the lowest value of the groups is also 1. So
when the function does the logical check z < m where z = c(group1,
group2) and m is the median, there are no values that are less than
the median value. Therefore there is only 1 level, and the fisher
test fails.
You would either need different data or adjust the function to be:
fisher.test(z <= m, g)$p.value
that way it's less than or equal to the median.
Hope that helps,
Josh
On Thu, May 27, 2010 at 7:24 AM, linda Porz <linda.p...@gmail.com> wrote:
> Hi all,
>
> I have found the following function online
>
> median.test<-function(y1,y2){
> z<-c(y1,y2)
> g <- rep(1:2, c(length(y1),length(y2)))
> m<-median(z)
> fisher.test(z<m,g)$p.value
> }
>
> in
>
> http://www.mail-archive.com/r-help@r-project.org/msg95278.html
>
> I have the following data
>
>> group1 <- c(2, 2, 2, 1, 4, 3, 1, 1)
>> group2 <- c(3, 1, 3, 1, 4, 1, 1, 1, 7, 1, 1, 1, 1, 1, 2)
>> median.test(w1,group1)
> [1] 1
>> median.test(group1,group2)
> Error in fisher.test(z < m, g) : 'x' and 'y' must have at least 2 levels
>
> I am very thankful in advance for any suggestion and help.
>
> Regards,
> Linda
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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>
--
Joshua Wiley
Senior in Psychology
University of California, Riverside
http://www.joshuawiley.com/
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