What about (not tested because no sample data, and I'm definitely unsure of my lapply() solution): lapply(data[2:13], FUN=as.character) lapply(data[2:13], FUN=as.numeric) ?
data[2:13] should correspond to the 12 Month columns. There might be a way to combine both lines but I don't think lapply would work with 2 function names. When I can't find a vectorized solution, or one with *apply, I use a for loop. I find it very easy to understand and it's fast enough for my "small" datasets HTH Ivan Le 5/26/2010 09:57, Mohan L a écrit : > > > On Wed, May 26, 2010 at 1:13 PM, Ivan Calandra > <ivan.calan...@uni-hamburg.de <mailto:ivan.calan...@uni-hamburg.de>> > wrote: > > Hi, > > What about: > as.numeric(as.character(data$State)) > ? > > > What I what is, I want to convert all the column excluding State to > factor to numeric in the data frame. So that I will send this data > frame to another function to total . > > Any help. > > Thanks & Rg > Mohan L > -- Ivan CALANDRA PhD Student University of Hamburg Biozentrum Grindel und Zoologisches Museum Abt. Säugetiere Martin-Luther-King-Platz 3 D-20146 Hamburg, GERMANY +49(0)40 42838 6231 ivan.calan...@uni-hamburg.de ********** http://www.for771.uni-bonn.de http://webapp5.rrz.uni-hamburg.de/mammals/eng/mitarbeiter.php [[alternative HTML version deleted]]
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