Hello
I have a data array with soil variables (caperf), in which the variable "clay"
is factor (as I see entering str(caperf)) . I need to do a regression model, so
I need to have arcilla (=clay) as a numeric variable. For that I have entered
as.numeric(as.character(arcilla))
and even entering
'as.numeric(levels(arcilla))[arcilla]'the variable is resting as factor, and
the linear model is not valid (for my purposes).
The decimal commas have been converted to decimal points, so I have no idea of
what to do.
Thanks a lot
Arantzazu Blanco Bernardeau
Dpto de Química Agrícola, Geología y Edafología
Universidad de Murcia-Campus de Espinardo
_________________________________________________________________
Diseñar aplicaciones tiene premio. ¡Si eres desarrollador no esperes más!
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
