But:
pose16$POSITION * pose16$SETTLEMENT is
[1] -702.90 244.77 166.48 2273.80 24876.00 2985.00 80.90
-15.95 2512.50 -2423.00
not:
c(702.9, -244.77, -166.48, -2273.8, -24876, -2985, -80.9, 15.95, -2512.5,
2423)
On Wed, May 12, 2010 at 11:53 AM, arnaud Gaboury
<arnaud.gabo...@gmail.com>wrote:
> The result is different with your code.
>
> My result is :
>
> pose16 <-
> structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L,
> 6L, 7L, 8L, 9L, 12L), .Label = c("COPPER May/10", "COTTON NO.2 Jul/10",
> "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10",
> "SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10",
> "WHEAT Jul/10", "PRIMARY NICKEL USD", "PRM HGH GD ALUMINIUM USD",
> "SPCL HIGH GRADE ZINC USD", "STANDARD LEAD USD"), class = "factor"),
> POSITION = c(2, -3, -2, -2, -18, -3, -5, 1, -5, 1), prix = c(702.9,
> -244.77, -166.48, -2273.8, -24876, -2985, -80.9, 15.95, -2512.5,
> 2423)), .Names = c("DESCRIPTION", "POSITION", "prix"), row.names =
> c("1",
> "2", "3", "4", "5", "6", "7", "8", "9", "51"), class = "data.frame")
>
> Your result is :
>
> pose16 <-
> structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L,
> 6L, 7L, 8L, 9L, 12L), .Label = c("COPPER May/10", "COTTON NO.2 Jul/10",
> "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10",
> "SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10",
> "WHEAT Jul/10", "PRIMARY NICKEL USD", "PRM HGH GD ALUMINIUM USD",
> "SPCL HIGH GRADE ZINC USD", "STANDARD LEAD USD"), class = "factor"),
> POSITION = c(2, -3, -2, -2, -18, -3, -5, 1, -5, 1), prix = c(-702.9,
> 244.77, 166.48, 2273.8, 24876, 2985, 80.9, -15.95, 2512.5,
> -2423)), .Names = c("DESCRIPTION", "POSITION", "prix"), row.names =
> c("1",
> "2", "3", "4", "5", "6", "7", "8", "9", "51"), class = "data.frame")
>
>
>
>
> From: Henrique Dallazuanna [mailto:www...@gmail.com]
> Sent: Wednesday, May 12, 2010 3:32 PM
> To: arnaud Gaboury
> Cc: r-help@r-project.org
> Subject: Re: [R] data frame subscription
>
> Try this:
>
> transform(pose16, prix = POSITION * SETTLEMENT, SETTLEMENT = NULL, POSITION
> = POSITION * -1)
>
> On Wed, May 12, 2010 at 9:50 AM, arnaud Gaboury <arnaud.gabo...@gmail.com>
> wrote:
> Dear group,
>
> Here is my df :
>
> pose16 <-
> structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L,
> 6L, 7L, 8L, 9L, 12L), .Label = c("COPPER May/10", "COTTON NO.2 Jul/10",
> "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10",
> "SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10",
> "WHEAT Jul/10", "PRIMARY NICKEL USD", "PRM HGH GD ALUMINIUM USD",
> "SPCL HIGH GRADE ZINC USD", "STANDARD LEAD USD"), class = "factor"),
> POSITION = c(-2, 3, 2, 2, 18, 3, 5, -1, 5, -1), SETTLEMENT = c(351.45,
> 81.59, 83.24, 1136.9, 1382, 995, 16.18, 15.95, 502.5, 2423
> )), .Names = c("DESCRIPTION", "POSITION", "SETTLEMENT"), row.names =
> c("1",
> "2", "3", "4", "5", "6", "7", "8", "9", "51"), class = "data.frame")
>
> Here is my code :
>
> >pose16$prix<-pose16[,2]*pose16[,3]
> >pose16<-pose16[,-3]
> >pose16[,-1]<- -pose16[,-1]
>
> It works fine, as the resulting df is what I want. I am just wandering if
> these 3 command lines can be writen in only 1 or 2 lines??
>
> TY for the help.
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
>
> --
> Henrique Dallazuanna
> Curitiba-Paraná-Brasil
> 25° 25' 40" S 49° 16' 22" O
>
>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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