Hi Sebastian, Please check if this does what you want:
nombreL <- c("Alvaro Perez", "Sebastián García", "Luis Gomez", "Jorge Rial", "Ronaldo Apud", "Ana María Bianco") nombreC <- c("Alvaro", "Ana","Jorge","Ronaldo", "Sebastian") func1 <- function(x) { grep(x, noquote(nombreL)) } lapply(noquote(nombreC), func1) ----------------Contact Details:------------------------------------------------------- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com (English) ---------------------------------------------------------------------------------------------- On Sat, May 8, 2010 at 10:46 AM, Sebastian Kruk <residuo.so...@gmail.com>wrote: > Hi, for example I have two list: > > nombreL <- c("Alvaro Perez", "Sebastián García", "Luis Gomez", "Jorge > Rial", "Ronaldo Apud",..., "Ana María Bianco") > nombreC <- c("Alvaro",..., "Ana",...,"Jorge",...,"Ronaldo", > "Sebastian",...) > > and my code is: > > cuenta <- 0 > topL <- length(nombreL) > topC <- length(nombreC) > for (i in 1:topL) { > for (j in 1:topC) { > k <- > grep(noquote(nombreL[i]),nombreC[j]) > if (length(k) > 0){ > > cuenta <- cuenta + 1 > } > } > > Thanks, > > Sebastian. > [[alternative HTML version deleted]]
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