Hi Sebastian,
Please check if this does what you want:

nombreL <- c("Alvaro Perez", "Sebastián García", "Luis Gomez", "Jorge Rial",
"Ronaldo Apud", "Ana María Bianco")
nombreC <- c("Alvaro", "Ana","Jorge","Ronaldo", "Sebastian")

func1 <- function(x)
{
grep(x, noquote(nombreL))
}
lapply(noquote(nombreC), func1)






----------------Contact
Details:-------------------------------------------------------
Contact me: tal.gal...@gmail.com |  972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English)
----------------------------------------------------------------------------------------------




On Sat, May 8, 2010 at 10:46 AM, Sebastian Kruk <residuo.so...@gmail.com>wrote:

> Hi, for example I have two list:
>
> nombreL <- c("Alvaro Perez", "Sebastián García", "Luis Gomez", "Jorge
> Rial", "Ronaldo Apud",..., "Ana María Bianco")
> nombreC <- c("Alvaro",..., "Ana",...,"Jorge",...,"Ronaldo",
> "Sebastian",...)
>
> and my code is:
>
> cuenta <- 0
> topL <- length(nombreL)
> topC <- length(nombreC)
> for (i in 1:topL) {
>                     for (j in 1:topC) {
>                                           k <-
> grep(noquote(nombreL[i]),nombreC[j])
>                                           if (length(k) > 0){
>
> cuenta <- cuenta + 1
>                                            }
>                      }
>
> Thanks,
>
> Sebastian.
>

        [[alternative HTML version deleted]]

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to