Hi Changbin, On Wed, May 5, 2010 at 6:46 PM, Changbin Du <changb...@gmail.com> wrote: > svm.fit<-svm(as.factor(out) ~ ., data=all_h, method="C-classification", > kernel="radial", cost=bestc, gamma=bestg, cross=10) # model fitting > > svm.pred<-predict(svm.fit, hh, decision.values = TRUE, probability = TRUE) # > find the probability, but can not find. > > attr(svm.pred, "probabilities") > >> attr(svm.pred, "probabilities") > 1 0 > 1 0 0 > 2 0 0 > 3 0 0 > 5 0 0 > 6 0 0 > 7 0 0 > 8 0 0 > 9 0 0 > > Hi, Dear R community, > > IN my data, the out variable is the target variable (0, and 1), hh is the > new data set does not contain the out variable. I trained the model svm.fit > in training data. And want to predict the out in the new data set hh. > > WHy the probabilities are both 0 in 1 and 0 class?
Look at the help for the svm function: ?svm Notice that there is a parameter in the svm function call named `probability` with a default value of FALSE. Try: svm.fit<-svm(as.factor(out) ~ ., data=all_h, method="C-classification", kernel="radial", cost=bestc, gamma=bestg, cross=10, probability=TRUE) -- Steve Lianoglou Graduate Student: Computational Systems Biology | Memorial Sloan-Kettering Cancer Center | Weill Medical College of Cornell University Contact Info: http://cbio.mskcc.org/~lianos/contact ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
