On 03/05/2010 2:43 PM, anderson nuel wrote:
I will sur that problem is coming from the first part of the test.
data[pa,k] is a vector because pa is a vector.
Coud you help me to solve this error.
If you want to test that all elements match, you should use
all(data[pa, k] == df[, j]) && data[ch, k] == i
The && says not to bother with the second test if the first one fails.
Duncan Murdoch
Best Regards
2010/4/30 Duncan Murdoch <murdoch.dun...@gmail.com>
> On 30/04/2010 4:19 AM, anderson nuel wrote:
>
>> Dear r-help,
>>
>> Could you help me to find a solution for this error:
>>
>> Il y a eu 50 avis ou plus (utilisez warnings() pour voir les 50 premiers)
>>
>>
>>
>>> warnings()
>>>
>>>
>> Messages d'avis :
>> 1: In if ((data[pa, k] == df[, j]) & (data[ch, k] == i)) { ... :
>> la condition a une longueur > 1 et seul le premier élément est utilisé
>>
>>
>
> It's saying that the condition has length > 1 and only the first element is
> used. This is probably coming from the first part of the test: data[pa,k]
> will be scalar, but df[,j] looks like a vector of every element in column j.
> The result is a vector with as many entries as you have rows in df. Only
> the first of them will be compared to data[pa, k].
>
> Duncan Murdoch
>
>> 2: In if ((data[pa, k] == df[, j]) & (data[ch, k] == i)) { ... :
>> la condition a une longueur > 1 et seul le premier élément est utilisé
>>
>>
>> ch=3
>> pa=c(1,2)
>> r=2
>> t=4
>> nb=15
>> ni=array(0,c( r,t))
>>
>> for ( i in 1:r){
>>
>> for (j in 1:t ){
>>
>> for (k in 1:nb){
>>
>> if ( (data[pa,k]== df[,j]) & (data[ch,k]==i)){
>>
>> ni[i,j]=ni[i,j]+1
>> }
>> }
>> }
>> }
>>
>> Best Regards
>>
>> [[alternative HTML version deleted]]
>>
>> ------------------------------------------------------------------------
>>
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>>
>>
>
>
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