Or better: tapply(x0, y0, mean)
On Mon, May 3, 2010 at 2:35 PM, Henrique Dallazuanna <www...@gmail.com>wrote: > Try this: > > rowsum(x0, y0)[,1]/table(y0) > > > On Mon, May 3, 2010 at 2:11 PM, song song <rprojecth...@gmail.com> wrote: > >> x0=rnorm(100) >> y0=rpois(100,3)+1 >> >> ind=as.data.frame(table(y0)) >> >> ind1=ind[,1] >> ind2=ind[,2] >> >> phi=NULL >> for (i in 1:length(ind2)){ >> phi[i]=sum(x0[y0==ind1[i]])/ind2[i] >> } >> >> [[alternative HTML version deleted]] >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> > > > > -- > Henrique Dallazuanna > Curitiba-Paraná-Brasil > 25° 25' 40" S 49° 16' 22" O > -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O [[alternative HTML version deleted]]
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.