Hi,
The regular expression (grep) below does not behave at all like the equivalent
in Python. Also, I would be happy if somebody could tell me what the R
equivalent for Python's re.findall is. The regex filters out any numbers not
enclosed by square brackets, including fractions (with either comma or dot as
the separator) and percentages. How should the R code below be modified so it
does the same as the Python code?
# python code
>>> import re
>>> pattern = "[^[[]([0-9]+[,.%]?[0-9]*)[^]]?"
>>> formula = "=832.1*R[1]K[1]*R[2]K[1]*25%"
>>> re.findall(pattern, formula)
['832.1', '25%']
# partial R code
> formula <- "=832,1*R[1]K[1]*R[2]K[1]*25%"
> pattern <- "[^[[]([0-9]+[,.%]?[0-9]*)[^]]?"
> grep(pattern, formula, value=TRUE, perl=TRUE)
[1] "=832,1*R[1]K[1]*R[2]K[1]*25%"
Thank you, and have a good weekend!
Cheers!!
Albert-Jan
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All right, but apart from the sanitation, the medicine, education, wine, public
order, irrigation, roads, a fresh water system, and public health, what have
the Romans ever done for us?
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