Thanks for advice, sorted now!
________________________________
From: Dennis Murphy [via R] <ml-node+1819620-944858377-225...@n4.nabble.com>
Sent: Sat, 10 April, 2010 2:18:33
Subject: Re: How to replace all non-maximum values in a row with 0
Hi:
This isn't much shorter than the previous solution, but here's another take,
operating row-wise.
A <- matrix (c(2, 3, 0, 0, 200, 30, 0, 0, 2, 50, 0, 0, 3, 0, 0,
0, 0, 8, 8, 0), nrow = 4, byrow=T)
# Write a vector function to apply to each row: begin by initializing a zero
# vector of length = no. columns. Next, find which indices of the row vector
x
# match the maximum. If that number is >1, return a zero vector, else
replace
# the index where the maximum resides to 1.
f <- function(x) {
o <- rep(0, length(x))
w <- which(x == max(x))
r <- if(length(w) > 1) {o} else {
o[w] <- 1; o}
r
}
# Test:
> t(apply(A, 1, f))
[,1] [,2] [,3] [,4] [,5]
[1,] 0 0 0 0 1
[2,] 0 0 0 0 1
[3,] 0 0 1 0 0
[4,] 0 0 0 0 0
HTH,
Dennis
On Fri, Apr 9, 2010 at 1:04 AM, burgundy <[hidden email]> wrote:
>
> Hi,
>
> I would like to replace all the max values per row with "1" and all other
> values with "0". If there are two max values, then "0" for both. Example:
>
> from:
> 2 3 0 0 200
> 30 0 0 2 50
> 0 0 3 0 0
> 0 0 8 8 0
>
> to:
> 0 0 0 0 1
> 0 0 0 0 1
> 0 0 1 0 0
> 0 0 0 0 0
>
> Thanks!
> --
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