On Apr 29, 2010, at 10:37 AM, RCulloch wrote:
Thanks Henrique,
that works! for anyone else as slow as me, just:
##Assign
x <- factor(dat.ID$ID2, labels = 1:7)
##Convert to dataframe
x <- as.data.frame(x)
The more typical methods for converting a factor to a character vector
would be:
(ff <- factor(substring("statistics", 1:10, 1:10), levels=letters))
levels(ff)[ff]
# [1] "s" "t" "a" "t" "i" "s" "t" "i" "c" "s"
as.character(ff)
# [1] "s" "t" "a" "t" "i" "s" "t" "i" "c" "s"
##Then bind to your data
z <- cbind(y,x)
Oooh. Not a good practice, at least for the newish useR. cbind and
rbind create matrices and as a consequence coerce all of their
elements to be of the same type. Numeric columns would become
character vectors. Not generally a desired result. This would be safer:
dat.I$ID2.cf <- as.character( factor(dat.ID$ID2, labels = 1:7) )
--
David.
Thanks again, I expected it to be more complicated!
Cheers,
Ross
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