Thanks Tengfei,
I have another question.
> df=data.frame(name=c('AA','BB',
> 'CC'),c1=c(23,123,5),c2=c(54,5,4),c3=c(0.999,1,23),c4=c(0.78,0.99,54))
> df
name c1 c2 c3 c4
1 AA 23 54 0.999 0.78
2 BB 123 5 1.000 0.99
3 CC 5 4 23.000 54.00
> df1=data.frame(name=c('BB','AA', 'DD'),c5=c(98,87,54),c6=c(7,6,3))
> df1
name c5 c6
1 BB 98 7
2 AA 87 6
3 DD 54 3
now I want to get interaction for df and df1 in terms of name. this is
name c1 c2 c3 c4 c5 c6
AA 23 54 0.999 0.78 87 6
BB 123 5 1.000 0.99 98 7
could give advice?
--- On Thu, 29/4/10, Tengfei Yin <yinteng...@gmail.com> wrote:
From: Tengfei Yin <yinteng...@gmail.com>
Subject: Re: [R] by funtion
To: "Petr PIKAL" <petr.pi...@precheza.cz>
Cc: "Yuan Jian" <jayuan2...@yahoo.com>, r-help@r-project.org
Received: Thursday, 29 April, 2010, 6:44 AM
Hi,
Thanks, actually I mentioned in the reply, you need to turn the matrix into
data frame in the end if use this method. e.g
> df=data.frame(name=c('AA','BB','AA'),c1=c(23,123,203),c2=c(54,5,98),c3=c(0.999,1,0.79),c4=c(0.78,0.99,0.99))
> aa=by(df[,2:5],df$name,mean)> dd=do.call('rbind',aa)> df=data.frame(dd)> df
> c1 c2 c3 c4AA 113 76 0.8945 0.885
BB 123 5 1.0000 0.990
Regards
TengfeiOn Thu, Apr 29, 2010 at 1:30 AM, Petr PIKAL <petr.pi...@precheza.cz>
wrote:
Hi
r-help-boun...@r-project.org napsal dne 29.04.2010 08:11:41:
> Hi
>
> you could try
>
> do.call('rbind',aa)
No, No, No. rbind and cbind binds vectors as rows or columns of
***matrix***, result is not a data frame
do.call("rbind",aa)
X069rutil X102anatas
105 26.9 7.9
200 22.8 10.6
400 30.6 13.3
600 50.8 20.6
800 78.7 NA
exp.df<-do.call("rbind",aa)
str(exp.df)
num [1:5, 1:2] 26.9 22.8 30.6 50.8 78.7 7.9 10.6 13.3 20.6 NA
- attr(*, "dimnames")=List of 2
..$ : chr [1:5] "105" "200" "400" "600" ...
..$ : chr [1:2] "X069rutil" "X102anatas"
If some object has rectangular shape and has column names it does not
automatically mean that it is data frame
Regards
Petr
>
>
> then turn the matrix into data frame
>
> regards
>
> Tengfei
>
> On Wed, Apr 28, 2010 at 10:56 PM, Yuan Jian <jayuan2...@yahoo.com>
wrote:
>
> > Hello,
> >
> > I have a data.frame:
> > name col1 col2 col3 col4
> > AA 23 54 0.999 0.78
> > BB 123 5 1 0.99
> > AA 203 98 0.79 0.99
> >
> > I want to get mean value data.frame in terms of name:
> >
> > name col1 col2 col3 col4
> >
> > AA 113.0000 76.0000 0.8945 0.8850
> >
> > BB 123.00 5.00 1.00 0.99
> >
> > I tried to use by function:
> >
> > >aa<-by(test[,2:5], feature, mean)
> > I found aa is "by" function.
> > > class(aa)
> > [1] "by"
> >
> > how can I transfer aa to a data frame?
> >
> > thanks
> > YU
> >
> >
> >
> >
> >
> >
> > [[alternative HTML version deleted]]
> >
> >
> > ______________________________________________
> > R-help@r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
> > http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
> >
>
>
> --
> Tengfei Yin
> MCDB PhD student
> 1620 Howe Hall, 2274,
> Iowa State University
> Ames, IA,50011-2274
> Homepage: www.tengfei.name
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
--
Tengfei Yin
MCDB PhD student
1620 Howe Hall, 2274,
Iowa State University
Ames, IA,50011-2274
Homepage: www.tengfei.name
[[alternative HTML version deleted]]
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