Greg has provided a solution. Just to answer the question of
why set_complement() is not doing what you think it should:

You need to change your *vectors* nom and denom to *sets*
with as.set().

 -Peter Ehlers

On 2010-04-23 9:42, Greg Snow wrote:
Here is a different approach that may work for you, or give you a starting 
place:

>  library(MASS)
>  fractions(60/(220*6))
[1] 1/22

>  From:r-help-boun...@r-project.org  [mailto:r-help-boun...@r-
>  project.org] On Behalf Of capybara!
>  Sent: Friday, April 23, 2010 7:49 AM
>  To:r-help@r-project.org
>  Subject: [R] cancelling in fraction
>
>
>  Dear All,
>
>  I have a fraction of 60./(220.*6.), which equals 1./22.
>  My question is how to cancel the fraction so I actually get 1/22
>  (actually I
>  just need the factor 22) using R. I tried it with prime factor
>  decomposition
>  from the package "schoolmath":
>
>  >  require("schoolmath")
>  Loading required package: schoolmath
>  >  nom<- prime.factor(60)
>  >  nom
>  [1] 2 2 3 5
>  >  denom<- prime.factor(220 * 6)
>  >  denom
>  [1]  2  2  2  3  5 11
>
>  So far so good, now I just need to take all elements which are in nom
>  out of
>  denom (if possible).
>  For this I use the package "sets", its function set_complement should
>  exactly do that, but:
>
>  >  require(sets)
>  >  set_complement(nom, denom)
>  {2, 2, 11}
>
>  It gives me {2,2,11} and 2 * 2 * 11 is 44 and not 22.
>  What am I doing wrong? Can anybody help me?
>  Is there maybe a more elegant way to cancel a fraction than by prime
>  factor
>  decomposition?
>
>  Many thanks in advance,
>
>  Hannes
>
>
>  --
>  View this message in context:http://r.789695.n4.nabble.com/cancelling-
>  in-fraction-tp2062218p2062218.html
>  Sent from the R help mailing list archive at Nabble.com.
>
>  ______________________________________________
>  R-help@r-project.org  mailing list
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>  and provide commented, minimal, self-contained, reproducible code.
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--
Peter Ehlers
University of Calgary

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