Dear group,
Here is my df : df <- structure(list(DESCRIPTION = c("PRM HGH GD ALUMINIUM USD 09/07/10 ", "PRM HGH GD ALUMINIUM USD 09/07/10 ", "PRIMARY NICKEL USD 04/06/10 " ), CREATED.DATE = structure(c(18361, 18361, 18325), class = "Date"), QUANITY = c(-1L, 1L, 1L), CLOSING.PRICE = c("2,415.90", "2,415.90", "25,755.71")), .Names = c("DESCRIPTION", "CREATED.DATE", "QUANITY", "CLOSING.PRICE"), row.names = c(NA, 3L), class = "data.frame") > > df DESCRIPTION CREATED.DATE QUANITY CLOSING.PRICE 1 PRM HGH GD ALUMINIUM USD 09/07/10 2020-04-09 -1 2,415.90 2 PRM HGH GD ALUMINIUM USD 09/07/10 2020-04-09 1 2,415.90 3 PRIMARY NICKEL USD 04/06/10 2020-03-04 1 25,755.71 In the DESCRIPTION column, I want to get rid of the date (09/07/10 .). I know the function substr(x, start, stop), but in my case, I need to indicate I want to start from the end of the vector, and I have no idea how to pass this argument. TY for any help *************************** Arnaud Gaboury Mobile: +41 79 392 79 56 BBM: 255B488F *************************** [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.