Would:
?merge
Work for you ?
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On Sun, Apr 18, 2010 at 7:30 PM, Laura Ferrero-Miliani <laur...@gmail.com>wrote:
> Dear very helpful friends,
>
> It is Sunday, there is no air traffic in Europe, what better to do
> than try and learn me some more R.
> I have the following example:
>
> owner <- c(1:4)
> animal <- c("cat", "dog", "cat", "dog")
> char.1 <- c("fluffy", "playful", "mean", "stupid")
> food <- c("cat food", "left-overs", "cat food", "dog food")
> char.2 <- c("lazy", "destructive", "antisocial", "goofy")
> color <- c("white", "brown", "black", "black")
> char.3 <- c("fat", "tiny", "evil", "big")
> age <- c(16, 2, 5, 10)
>
> pet.data <- data.frame(owner, animal, char.1, food, char.2,
> color, char.3, age)
>
> animal <- c("cat", "dog")
> v1 <- c("fluffy", "big")
> v2 <- c("fat", "stupid")
>
> pet.key <- data.frame(animal, v1, v2)
>
>
> Now I would like to compare my pet.key to my pet.data and add a
> variable to pet.data with that result.
> So for each "cat" in pet.data, char.1, char.2 and char.3 should
> contain "fluffy" AND "fat" for a complete match, or "fluffy" OR "fat"
> for a partial match, and so on.
>
> I don't know where to start. I *think* I should be using %in%, but I
> don't know how to build the expression so it works (so far I have
> tried and have gotten from lists to a weird array as a result!)
>
> btw, what if my data and my key contains repeated values e.g.
>
> animal v1 v2
> cat fluffy fluffy
>
>
> Any suggestions?
>
>
> Thanks in advance,
>
> Laura
>
> ______________________________________________
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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