Hi: Try this:
with(rle(x), data.frame(Level = values, Count = lengths)) Level Count 1 1 3 2 0 4 3 1 2 4 0 3 5 1 2 6 0 1 HTH, Dennis On Wed, Apr 14, 2010 at 7:11 PM, Pete B <peter.breckn...@bp.com> wrote: > > Hi All > > I have a vector x containing 2 levels > > x = c(1,1,1,0,0,0,0,1,1,0,0,0,1,1,0) > > I would like to derive the following summarization > > Level Count > 1 3 > 0 4 > 1 2 > 0 3 > 1 2 > 0 1 > > I have generated an inelegant solution using lags and loops but feel sure > that there must be a better approach. If anyone has any thoughts I would be > very grateful if you would share them. > > Thanks and best regards > > Pete > -- > View this message in context: > http://n4.nabble.com/Summarization-tp1840718p1840718.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
