Wow, those are cool functions! Â Thanks!
--- On Sat, 4/10/10, Henrique Dallazuanna [via R]
<ml-node+1835454-939980203-179...@n4.nabble.com> wrote:
From: Henrique Dallazuanna [via R]
<ml-node+1835454-939980203-179...@n4.nabble.com>
Subject: Re: str: how to use "no list" recursively?
To: "Jeff Brown" <dopethatwantsc...@yahoo.com>
Date: Saturday, April 10, 2010, 12:02 PM
Try this:
cat(gsub(":List of .*", "", capture.output(str(x, no.list = TRUE))), sep = '\n')
On Fri, Apr 9, 2010 at 11:11 PM, Jeff Brown <[hidden email]> wrote:
>
> Hi,
>
> In the help file for str(), the following line appears: "no.list    Â
> logical;
> if true, no âlist of ...â nor the class are printed". Â However, that
> appears
> to be true only on the top level; setting no.list to TRUE still leaves the
> remaining levels with the `list of ...' statement intact:
>
>> x <- list(
> + Â Â Â a = list(list()),
> + Â Â Â b = list(list())
> + );
>> str(x)
> List of 2
> Â $ a:List of 1
> Â ..$ : list()
> Â $ b:List of 1
> Â ..$ : list()
>> str(x, no.list = TRUE)
> Â $ a:List of 1
> Â ..$ : list()
> Â $ b:List of 1
> Â ..$ : list()
>>
>
> For readability reasons, I'd like to keep the indented $ signs and the names
> of the sub-lists but suppress printing of `List of ...'. Â Is that possible?
>
> Thanks,
> Jeff
> --
> View this message in context:
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>
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>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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