David,
all.equal() only tells how many mismatches there are including missing
values but it doesn't tell me the location of each mismatch.
For example, if I have one NA mismatch and three numerical mismatches,
all.equal(a,b) gives
[1] "Component 2: 'is.NA' value mismatch: 1 in current 0 in target"
[2] "Component 3: 3 string mismatches"
This only tells the missing value mismatch is in the second column
(component) and 3 numerical mismatches in the third column. But no row
information
which(mapply(identical,unlist(a),unlist(b))==FALSE) gives
TIME5 DV1 DV2 DV17
85 161 162 177
It tells me exactly which columns and rows to have the mismatches. In this
case is column "TIME" row 5 and column "DV" rows 1, 2 and 17. You can ignore
the serial numbers that followed.
Jun
On Thu, Apr 8, 2010 at 1:58 PM, David Winsemius <dwinsem...@comcast.net>wrote:
>
> On Apr 8, 2010, at 1:34 PM, Jun Shen wrote:
>
> David,
>>
>> Thanks for the suggestion. Now I have worked out a general solution.
>>
>> Assume "a" and "b" are two data frames with same dimensions
>>
>> 1. Call identical(a,b) to get an overall assessment. If you get a FALSE
>> 2. Call which(mapply(identical,unlist(a),unlist(b))==FALSE), you will get
>> a result like
>> TIME5
>> 85
>> which means, the row 5 and the column with name "TIME" is different. This
>> also works for missing values. Thanks for everyone.
>>
>
> Looks that all.equal is already set up to provide such a service:
>
> > all.equal(df1,df2)
> [1] "Component 1: 'is.NA' value mismatch: 1 in current 0 in target"
>
> I was under the misimpression that all.equal was for approximate equality
> of numeric values but that only appears to be part of its design.
>
> --
> David.
>
>
>
>> Jun Shen from Millipore
>>
>> On Thu, Apr 8, 2010 at 9:08 AM, David Winsemius <dwinsem...@comcast.net>
>> wrote:
>>
>> On Apr 8, 2010, at 9:47 AM, Jun Shen wrote:
>>
>> Dear David, Erik and Charles,
>>
>> Thank you for your input. Both mapply() and which() can do the job. Just
>> one
>> exception. If there is a missing value as NA in the data frame "a" and a
>> data point (either numerical or character) in the corresponding position
>> of
>> "b", then mapply() only returns NA for that position rather than "FALSE",
>> and which() cannot pick up that position either. Thanks again.
>>
>>
>> You seem to have changed the programming challenge from identification to
>> replicating identical(). If so then you can get closer with wrapping
>> isTRUE(all() around the mapply("==" , attributes( ...), ...) step, and
>> wrap the "==" call in isTRUE(all(.))
>>
>> > isTRUE(all(mapply("==", df1, df2)) )
>> [1] FALSE since all(c(NA, TRUE, TRUE)) == NA and isTRUE(NA) == FALSE
>>
>> --
>> David.
>>
>>
>>
>>
>> Jun
>>
>> On Wed, Apr 7, 2010 at 10:46 PM, Charles C. Berry <cbe...@tajo.ucsd.edu
>> >wrote:
>>
>> On Wed, 7 Apr 2010, Jun Shen wrote:
>>
>> Dear all,
>>
>> I understand identical (a,b) will tell me if a and b are exactly the same
>> or
>> not. But what if they are different, is there anyway to tell which
>> element(s) are different? Thanks.
>>
>>
>> which( a != b, arr.ind = TRUE)
>>
>> HTH,
>>
>> Chuck
>>
>>
>> Jun
>>
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
>> Charles C. Berry (858) 534-2098
>> Dept of Family/Preventive
>> Medicine
>> E mailto:cbe...@tajo.ucsd.edu UC San Diego
>> http://famprevmed.ucsd.edu/faculty/cberry/ La Jolla, San Diego
>> 92093-0901
>>
>>
>>
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>> David Winsemius, MD
>> West Hartford, CT
>>
>>
>>
> David Winsemius, MD
> West Hartford, CT
>
>
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