On Apr 6, 2010, at 10:42 AM, marta rufino wrote:

Dear R-list members,

I am calculating the linear extrapolation for a data set, using the function
found in Hmisc.

x=c(0.0265,-0.0003,0.0142,0.0263,0.0634,0.1145,0.2504)
y=c(58,107,152,239,362,512,724)
x1=0.0393216
approxExtrap(x,y,x1, method="linear")
approx(x,y,x1)

#to see what is happening:
plot(x, y, typ="o")
abline(v=x1, col=8)


Which gives x=0.03 and y=163, instead of the expectable which would be close
to y=300.
Any ideia why this is happening or how to sort this out?

Have you tried:

 plot(x,y)
 lines(x, approxfun(x,y)(x))

It would clue you in to the fact that your x argument was not ordered and that the "next x" after 0.0263 is actually x[1] == 0.0265. Now try:

> approxfun(x,y)(0.0263+seq(0,.04, by=0.001)  )
[1] 239.00000 64.59079 72.82927 81.06775 89.30623 97.54472 105.78320 114.02168 122.26016 [10] 130.49864 138.73713 146.97561 155.21409 163.45257 171.69106 179.92954 188.16802 196.40650 [19] 204.64499 212.88347 221.12195 229.36043 237.59892 245.83740 254.07588 262.31436 270.55285 [28] 278.79133 287.02981 295.26829 303.50678 311.74526 319.98374 328.22222 336.46070 344.69919
[37] 352.93767 361.17615 364.64188 367.57730 370.51272

And I think it will be clearer what is happening.

In retrospect it would have been clearer to do this initially:
> plot(x,y)
> lines(seq(0.02, 0.2, by= 0.001), approxfun(x,y)(seq(0.02, 0.2, by= 0.001)) )


--
David.


Thank you vey much in advance,
Best wishes,
Marta

--
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Laboratório Nacional de Energia e Geologia, I.P.

Estrada da Portela, Zambujal - Alfragide
Apartado 7586, 2720-866 Amadora
www.lneg.pt

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