Snippet of my code:
library(foreign)
function1 <- function(y,t){
###do some matrix operations ##
}
function2 <- function(y){
y1 = permute(y)
F1 = function1(y1)
}
setwd("C:\\Results\\") ## Read Multiple Files
files.total = list.files()
for (j in files.total){
table1 = read.table(j)
### do some operations
### Call functions1 and function2
### get the result stored in object result
message("Result for\t\",j,"\t",result)
rm(table1,result) ### in short I am removing all the objects except j and
function calls -- a crude way of getting the independent results and there
is no dependency on ###previous results
}
Now, I would like to verify that it is calculating everything from scratch
and it is not taking any results from the previous iteration. I am doing
this because I am not getting the result that I want, also I have verified
that my code works fine without any errors for the ones when I am reading it
only once and not multiple times.
Thanks.
Regards,
Ayush
On Thu, Apr 1, 2010 at 11:44 AM, Tal Galili <tal.gal...@gmail.com> wrote:
> Hi Ayush,
> Could you supply with a simple code to try to give an answer on ?
>
> Thanks,
> Tal
>
>
>
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>
> On Thu, Apr 1, 2010 at 6:24 PM, Ayush Raman <ayushra...@gmail.com> wrote:
>
>> Hi,
>>
>> I would like to know if there is some debugger in R where I can check that
>> I
>> am not using or not doing calculation on my previously stored objects. I
>> can't use rm (list = ls()) to remove all the objects since I am using a
>> for
>> loop for reading 500 files and making making common calculation for each
>> file, therefore I need to keep the track of my iterator. Is it possible to
>> remove everything except the iterator and see that my answers for each
>> iterations are not getting compiled on previous answers.
>>
>> Thanks.
>>
>> --
>> Regards,
>> Ayush Raman
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
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>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>
--
Regards,
Ayush Raman
[[alternative HTML version deleted]]
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