On Mar 30, 2010, at 1:41 PM, Dgnn wrote:
Sorry for not supplying some example code for the above example.
Here's an
example list 'a' with histogram elements A, B, and C which are also
lists.
That is not code. That is output. It is not clear how "a" was created
a
$A
$breaks
If you want to access the breaks element then try any of these
untested guesses:
a$A$breaks
or:
a["A"][["breaks"]]
a$A["breaks"]
With the example on the help page for hist() you would get:
> a <- hist(islands)
> a["breaks"]
$breaks
[1] 0 2000 4000 6000 8000 10000 12000 14000 16000 18000
> a[["breaks"]]
[1] 0 2000 4000 6000 8000 10000 12000 14000 16000 18000
[1] -80 -70 -60 -50 -40 -30 -20 -10 0 10 20 30 40 50 60
$counts
[1] 1 0 0 2 29 120 301 433 421 265 93 43 9 3
$intensities
[1] 5.81e-05 0.000000e+00 0.000000e+00 1.162791e-04 1.686047e-03
6.976744e-03 1.750000e-02
[8] 2.512e-02 2.447674e-02 1.540698e-02 5.406977e-03 2.500000e-03
5.232558e-04 1.744186e-04
$density
[1] 5.813-05 0.000000e+00 0.000000e+00 1.162791e-04 1.686047e-03
6.976744e-03 1.750000e-02
[8] 2.517442e-02 2.447674e-02 1.540698e-02 5.406977e-03 2.500000e-03
5.232558e-04 1.744186e-04
$mids
[1] -75 -65 -55 -45 -35 -25 -15 -5 5 15 25 35 45 55
$xname
[1] "X[[1L]]"
$equidist
[1] TRUE
attr(,"class")
[1] "histogram"
$B
$breaks
[1] -40 -35 -30 -25 -20 -15 -10 -5 0 5 10 15 20 25 30 35
$counts
[1] 2 1 3 20 86 225 396 408 404 294 182 125 38 11 1
...
$C
...
Is there a way to index the $xname element from each of the elements
of a?
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David Winsemius, MD
West Hartford, CT
______________________________________________
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and provide commented, minimal, self-contained, reproducible code.
