I wrote a different code - but it takes twice as long as my original code. :( However, I thought I should share it as well - because the second part of the code is fast - it's the first part that's slow. Maybe there is a way to fix the first part... Thank you!
group.var<-"group" subgroups<-levels(frame[[group.var]]) system.time({ means.no.zeros<-list() for(i in 1:length(subgroups)){ # SLOW part of the code row.of.means<-as.data.frame(t(colMeans(frame[frame[[group.var]] %in% subgroups[i],names.used],na.rm=T))) nr.of.rows<-(dim(frame[frame[[group.var]] %in% subgroups[i],])[1]) means.no.zeros[[i]]<-as.data.frame(matrix(nrow=nr.of.rows,ncol=length(names.used))) means.no.zeros[[i]]<-row.of.means for(z in 1:nr.of.rows){ #z<-1 means.no.zeros[[i]][z,] = row.of.means } } means.no.zeros<-do.call(rbind,means.no.zeros) }) system.time({ #FAST part of the code frame[names.used]<-frame[names.used]/means.no.zeros }) ################################################################################ On Tue, Mar 30, 2010 at 11:04 AM, Dimitri Liakhovitski <ld7...@gmail.com> wrote: > Dear R-ers, > > I have a large data frame (several thousands of rows and about 2.5 > thousand columns). One variable ("group") is a grouping variable with > over 30 levels. And I have a lot of NAs. > For each variable, I need to divide each value by variable mean - by > subgroup. I have the code but it's way too slow - takes me about 1.5 > hours. > Below is a data example and my code that is too slow. Is there a > different, faster way of doing the same thing? > Thanks a lot for your advice! > > Dimitri > > > # Building an example frame - with groups and a lot of NAs: > set.seed(1234) > frame<-data.frame(group=rep(paste("group",1:10),10),a=rnorm(1:100),b=rnorm(1:100),c=rnorm(1:100),d=rnorm(1:100),e=rnorm(1:100),f=rnorm(1:100),g=rnorm(1:100)) > frame<-frame[order(frame$group),] > names.used<-names(frame)[2:length(frame)] > set.seed(1234) > for(i in names.used){ > i.for.NA<-sample(1:100,60) > frame[[i]][i.for.NA]<-NA > } > frame > > ### Code that does what's needed but is too slow: > Start<-Sys.time() > frame <- do.call(cbind, lapply(names.used, function(x){ > unlist(by(frame, frame$group, function(y) y[,x] / mean(y[,x],na.rm=T))) > })) > Finish<-Sys.time() > print(Finish-Start) # Takes too long > > -- > Dimitri Liakhovitski > Ninah.com > dimitri.liakhovit...@ninah.com > -- Dimitri Liakhovitski Ninah.com dimitri.liakhovit...@ninah.com ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.