Hi,
what about: assign()?
I don't know if it's really important, but I've always seen the
assignment operator the other way (<-)
HTH,
Ivan
Le 3/29/2010 13:14, dgallego a écrit :
Dear list,
I would generate a loop:
a<-c(1:98)
for (i in a )
{
cbind(vor.tile[[i]]$x, vor.tile[[i]]$y)->p
rbind(p,c(p[1,]))->p.c
Polygon(p.c)->pc.p
Polygons(list(pc.p),sprintf("p%s",i))->pc.ps
sprintf("pc.ps%s",i)<-pc.ps
}
I need to obtain 98 pc.ps objects (like: pc.ps1, pc.ps2....pc.ps98) but I
d'ont use sprintf for it.
How can made it?
many tanks in advance
--
Ivan CALANDRA
PhD Student
University of Hamburg
Biozentrum Grindel und Zoologisches Museum
Abt. Säugetiere
Martin-Luther-King-Platz 3
D-20146 Hamburg, GERMANY
+49(0)40 42838 6231
ivan.calan...@uni-hamburg.de
**********
http://www.for771.uni-bonn.de
http://webapp5.rrz.uni-hamburg.de/mammals/eng/mitarbeiter.php
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