Hi,
I don't really understand what the problem is... There is no duplicated
column... Maybe you mean the row names? If it is so, then just don't use
row names.
Ivan
Le 3/17/2010 10:45, Carlos Petti a écrit :
Dear list,
I have a contingency table :
a<- letters[1:3]
t<- table(a)
I'm looking for a way to transform this table into data frame, as follows :
Freq
a 1
b 1
c 1
I used :
df<- as.data.frame(t, row.names = names(t))
But, this function do not remove the duplicated column. Do you know the
solution ?
Thanks in advance,
Carlos
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