On Mar 13, 2010, at 11:46 AM, Javier wrote:
Dear users,
Is anyone out there on a Saturday to answer this easy question?
I have the "yo" object data in a "list" format:
str(yo)
num [1:259, 1:173] 16.3 NA NA NA NA ...
- attr(*, "dimnames")=List of 2
..$ x: chr [1:259] "367319" "367329" "367309" "367339" ...
..$ y: chr [1:173] "780175" "780185" "780195" "780205" ...
length(yo)
[1] 44807
where x is the name of the rows and y the name of the columns
(coordinates)
of a matrix of 44807 values
how can I get a data.frame with these three columns: x, y, values
?as.data.frame.table
> as.data.frame.table(matrix((1:16)/16, ncol=2))
Var1 Var2 Freq
1 A A 0.0625
2 B A 0.1250
3 C A 0.1875
4 D A 0.2500
5 E A 0.3125
6 F A 0.3750
7 G A 0.4375
8 H A 0.5000
9 A B 0.5625
10 B B 0.6250
11 C B 0.6875
12 D B 0.7500
13 E B 0.8125
14 F B 0.8750
15 G B 0.9375
16 H B 1.0000
You will need to relabel the columns but the "names()<-" function will
suffice.
--
David.
Many thanks to the Saturday working people.
Javier
and I want to produce a data frame
--
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David Winsemius, MD
West Hartford, CT
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