Then:
subset(x, grepl('410|I25', main_condition))
On Wed, Mar 3, 2010 at 11:59 AM, Newbie19_02 <nvanzuy...@gmail.com> wrote:
>
> Hi,
>
> That was a good suggestion but I should have been more specific,
> PROCHI Date_admission main_condition
> CAO3121534 15/08/2006 I501
> 28394 CAO3121534 18/04/1999 I251
> 28395 CAO3121534 18/10/1993 4109
> 28396 CAO3121534 19/01/1988 71946
> 28397 CAO3121534 20/04/1999 I251
> 28398 CAO3121534 21/04/1999 I251
> 28399 CAO3121534 21/05/1998 Z048
> 28400 CAO3121534 21/10/1993 4109
> 28401 CAO3121534 25/02/2002 R634
> 28402 CAO3121534 26/01/2003 B349
> 28403 CAO3121534 27/08/1998 M179
> 28404 CAO3121534 28/05/1999 I501
> 28405 CAO3121534 30/09/1997 I259
> 28406 CAO3121534 31/08/2007 H830
> 28407 CAO3121560 07/07/2000 D688
>
> So let's say that I want to subset but only by characters beginning with 410
> and I25?
> grep returns any character containing the pattern and so is not entirely
> suitable to the extended example. Though it works almost perfectly. Is
> there a way to make it match the first three letters?
>
> THanks,
> Natalie
> --
> View this message in context:
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>
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--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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