Try this:
> aggregate(daily.dat, format(time(daily.dat), "%m"), sd)
01 02 03 04 05 06 07 08
0.9473855 0.8577099 1.0614892 1.0120308 1.1301652 1.0969453 1.0327717 1.0392682
09 10 11 12
1.0276672 1.0173960 0.8953093 1.0964024
On Wed, Feb 24, 2010 at 8:31 AM, Bogaso <bogaso.christo...@gmail.com> wrote:
>
> Thanks Gabor for this reply. Your first reply answers my question, however
> end is not. Here you said :
>
>> set.seed(1)
>> daily.dat <- zooreg(rnorm(500), start=as.Date("2000-01-01"), frequency=1)
>> aggregate(daily.dat, as.yearmon, sd)
> Jan 2000 Feb 2000 Mar 2000 Apr 2000 May 2000 Jun 2000 Jul 2000 Aug
> 2000
> 0.9370553 0.7743405 0.9514569 0.8813805 0.9188229 1.0969453 1.0327717
> 1.0392682
> Sep 2000 Oct 2000 Nov 2000 Dec 2000 Jan 2001 Feb 2001 Mar 2001 Apr
> 2001
> 1.0276672 1.0173960 0.8953093 1.0964024 0.9696928 0.9507952 1.1275021
> 1.1410237
> May 2001
> 1.5286202
>
> But what I want is, to aggregate "all" data on a particular month for all
> years and apply statistics on that aggregated data. Therefore I should get
> only 12 values (for 12 months) not 17 values. Is there any way to do that?
>
> Thanks,
> --
> View this message in context:
> http://n4.nabble.com/Question-on-Zoo-object-tp1567207p1567464.html
> Sent from the R help mailing list archive at Nabble.com.
>
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