Try this: sapply(x, '[', 'p.value')
On Thu, Feb 18, 2010 at 5:21 PM, chipmaney <chipma...@hotmail.com> wrote: > > I have run a kruskal.test() using the by() function, which returns a list of > results like the following (subset of results): > > Herb.df$ID: 4-2 > Kruskal-Wallis chi-squared = 18.93, df = 7, p-value = 0.00841 > -------------------------------------------------------------------- > Herb.df$ID: 44-1 > Kruskal-Wallis chi-squared = 4.43, df = 6, p-value = 0.6187 > > > So then, how do extract a vector of p-values (i.e., result$p.value) for > every element in the list? > > > > -- > View this message in context: > http://n4.nabble.com/Extracting-values-from-a-list-tp1560701p1560701.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
