After reading the R news, I've tried this code and it works:
> rapply(list(names(test),test), write.csv, file="filename.csv",
append=T, row.names=F)
However, the output is structured like this:
names(test)[[1]]
names(test)[[2]]
etc...
test[[1]]
test[[2]]
etc...
I would like to alternate names(test) and test in the output. The
desired output would be structured like this:
names(test)[[1]]
test[[1]]
names(test)[[2]]
test[[2]]
etc...
Can someone guide me for that step? Better solutions for the whole thing
are of course welcomed!
Thanks a lot
Ivan
Le 2/10/2010 10:50, Ivan Calandra a écrit :
Hi everybody!
I'm still quite new in R and I don't really understand this whole
"vectorization" thing.
For now, I use a for loop (and it works fine), but I think it would be
useful to replace it.
I want to export the result of a test statistic, which is stored as a
list, into a csv file. I therefore have to export each element of the
list separately.
Here is the code:
----
str(test)
List of 3
$ output : num [1:15, 1:6] 1 2 3 4 5 6 7 8 9 10 ...
..- attr(*, "dimnames")=List of 2
.. ..$ : NULL
.. ..$ : chr [1:6] "con.num" "psihat" "p.value" "p.crit" ...
$ con : num [1:6, 1:15] 1 -1 0 0 0 0 1 0 -1 0 ...
$ num.sig: int 0
for (i in 1:3){
write.csv(test[[i]], file="filename.csv", append=T, quote=F,
row.names=T)
}
----
As I said, I don't completely understand, but I think one of these
"apply" function might do what I need.
Thanks in advance
Ivan
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
