Hi
r-help-boun...@r-project.org napsal dne 02.02.2010 22:16:06:
>
> 'fraid not :-((
>
> tapply( data, groups, weighted.mean, weights)
tapply(seq(along=lll), rrr, function(i, x, w) weighted.mean(x[i], w[i]),
x=lll, w=ttt)
If you want to subset more than one thing, subset the index vector.
The above help I obtained from Prof.Ripley several years ago so (untested)
tapply( seq(along=data), groups, function (i, x, w) weighted.mean(x[i],
w[i]), x=data, w=weights)
I believe it shall still work.
Regards
Petr
>
> won't work because the *entire* weights vector is passed as the 2nd arg
to
> weighted.means. But weighted.mean needs 'weights' to be split in the
same
> way as 'data' -- the first and 2nd args need to correspond.
>
>
> Jorge Ivan Velez wrote:
> >
> > Hi sjaffem,
> >
> > You were almost there:
> >
> > tapply( yourdata, groups, weighted.mean, weights)
> >
> > See ?tapply for more information.
> >
> > HTH,
> > Jorge
> >
> >
> >
>
> --
> View this message in context:
http://n4.nabble.com/tapply-for-function-taking-
> of-1-argument-tp1460392p1460419.html
> Sent from the R help mailing list archive at Nabble.com.
>
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